Question

What is the distance between (5, –1) and (5, –4)? On a coordinate plane, points are at (5, negative 1) and (5, negative 4). 1 unit 3 units 4 units 5 units

Answer 1

Usually, the formula to find the distance between points

$A=(A_x, A_y),\quad B=(B_x, B_y)$

is

$d=\sqrt{(A_x-B_x)^2+(A_y-B_y)^2}$

However, if two points share one coordinate, this formula simplifies a lot. In this case, for example, we have $A_x=B_x$. So, the formula becomes

$d=\sqrt{(A_x-A_x)^2+(A_y-B_y)^2}=\sqrt{(A_y-B_y)^2}=|A_y-B_y|$

And the absolute value of the difference of the y coordinates is

$|-1-(-4)|=|-1+4|=3$

So, the two points are 3 units apart.

Answer 2

Answer:

Your answer is B

Step-by-step explanation:

Hope this helps!!