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VARVARA [1.3K]
1 year ago
5

The student body at an after-school program consists only of 6th graders, 7th graders, and 8th graders. The ratio of 6th graders

to 8th graders is 17:28. If a total of 110 students attend the program, n of whom are 7th graders, what is a possible value of n?​
Mathematics
1 answer:
Aleksandr [31]1 year ago
8 0

Step-by-step explanation:

the correct answer is60

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Please help me with this question!! :)
Gre4nikov [31]

Answer:

D. The last 26/8, 3-32, -Pi, -4 2/3

Step-by-step explanation:

26/8= 3.25

3-32=3.17

-Pi= -3.14

-4 2/3= -4.67

6 0
8 months ago
Brandon mows the neighbor's yard to earn extra
olganol [36]

Answer:

7 is the answer you're looking for

5 0
2 years ago
You estimated the average rental cost of a 2 bedroom apartment in Denton. A random sample of 16 apartments was taken. The sample
Zigmanuir [339]

Answer:

The new sample size required in order to have the same confidence 95% and reduce the margin of erro to $60 is:

n=28

Step-by-step explanation:

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma=160)  

And the distribution for \bar X is:

\bar X \sim N(\mu, \frac{160}{\sqrt{n}})  

We know that the margin of error for a confidence interval is given by:  

Me=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)  

The next step would be find the value of \z_{\alpha/2}, \alpha=1-0.95=0.05 and \alpha/2=0.025  

Using the normal standard table, excel or a calculator we see that:  

z_{\alpha/2}=\pm 1.96  

If we solve for n from formula (1) we got:  

\sqrt{n}=\frac{z_{\alpha/2} \sigma}{Me}  

n=(\frac{z_{\alpha/2} \sigma}{Me})^2  

And we have everything to replace into the formula:  

n=(\frac{1.96(160)}{78.4})^2 =16  

And this value agrees with the sample size given.

For the case of the problem we ar einterested on Me= $60, and we need to find the new sample size required to mantain the confidence level at 95%. We know that n is given by this formula:

n=(\frac{z_{\alpha/2} \sigma}{Me})^2  

And now we can replace the new value of Me and see what we got, like this:

n=(\frac{1.96*160}{60})^2 =27.32

And if we round up the answer we see that the value of n to ensure the margin of error required Me=\pm 60 $ is n=28.    

5 0
2 years ago
At a concert, the number of security guards needed is based on the average density of people in an area of 25'x25' called a bloc
ira [324]

find total area  by multiplying  350' x 200' = 70,00 sq ft

area of one block, multiply 25' x 25' = 625 sq ft  = area for one Security guard

divide area for one security guard into total area of facility  70,000 / 625 =

112 security guards

find how many people for each block = 70,000 / 625 = 112 blocks

12,000 people divided by 112 blocks = 12,000 / 112 = 107.14 rounded to nearest 10 = 110 people per block

3 0
3 years ago
3) Ming and Amanda are selling pies for a school fundraiser. Customers can buy blueberry pics and lemon meringue pies. Ming sold
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Umm i think it would be 35$
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2 years ago
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