Answer:
C. H0 : p = 0.8 H 1 : p ≠ 0.8
The test is:_____.
c. two-tailed
The test statistic is:______p ± z (base alpha by 2)
The p-value is:_____. 0.09887
Based on this we:_____.
B. Reject the null hypothesis.
Step-by-step explanation:
We formulate null and alternative hypotheses as proportion of people who own cats is significantly different than 80%.
H0 : p = 0.8 H 1 : p ≠ 0.8
The alternative hypothesis H1 is that the 80% of the proportion is different and null hypothesis is , it is same.
For a two tailed test for significance level = 0.2 we have critical value ± 1.28.
We have alpha equal to 0.2 for a two tailed test . We divided alpha with 2 to get the answer for a two tailed test. When divided by two it gives 0.1 and the corresponding value is ± 1.28
The test statistic is
p ± z (base alpha by 2)
Where p = 0.8 , q = 1-p= 1-0.8= 0.2
n= 200
Putting the values
0.8 ± 1.28
0.8 ± 0.03620
0.8362, 0.7638
As the calculated value of z lies within the critical region we reject the null hypothesis.
Answer:
45×7
Step-by-step explanation:
Given that, Nathan shares out 12 sweets, if he gives Yasmin 1 sweet for 3 sweets he buys, Nathan will get 9 sweets.
<h3>How many sweets does Nathan gets?</h3>
Given that, Nathan shares out 12 sweets, he gives Yasmin 1 sweet for 3 sweets he buys.
Let the sweet be represented by x
For each x sweet for Yasmin, Nathan gets 3x sweets
Hence
x + 3x = 12
We solve for x
4x = 12
x = 12/4
x = 3
Hence;
Yasmin gets x sweet = 3
Nathan gets 3x sweets = 3 × 3 = 9
Given that, Nathan shares out 12 sweets, if he gives Yasmin 1 sweet for 3 sweets he buys, Nathan will get 9 sweets.
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Exactly half of these integers are odd (1, 3, 5, ..., 29) so the probability of selecting an odd number is
.
Answer:
You can use equation or use a calculator.
Step-by-step explanation: