Answer:
A and B
Step-by-step explanation:
Not C because
-5.75 < -5.45
In D, all are less than -5.45
It is important to notice firs of all that the train with no stop acceleration and them no stop acceleration would have a faster travel between stops. given this is safe to assume that there is a period during while the train is not accelerating nor decelerating. To find the time that is speed is constant
let's assume non-stop accelerating and decelerating and the time lost (subtraction of both) is the time the train had constant speed:
assuming same time accelerating a decelerating we have that the distance is
x = voT + 1/2aT^2 (initiial speed = 0) (0.25 miles = 1320 feets)
1320 = 1/2 (8)(T/2)^2
T/2 = 18.17 seg
T = 36.34 seg
time of constant speed
T = 41 -36.34 = 4.66 seg
maximum speed
v = v0 + aT (initial speed = 0)
v = 8(18.17) (time accelerating)
v = 145.36 feets/sec
distance at full speed
x = v*t
x = 145.36*4.66 = 677.38 feets
Answer: 9
x
3
(
5
x
+
8
)
Step-by-step explanation:
Factor 9
x
3 out of 45
x
4
+
72x
3
.
In the given question the length and width of the plot are already given. although there is no direct specification regarding the one that is length or the one that is the width, so it can be taken as your own choice. This will not affect the ultimate answer.
So
Area of the rectangular plot = Length * Width
= 11.7 * 15.4 square cm
= 180.18 square cm
So the area of the rectangular plot as can be seen from the above deduction is 180.18 square centimeter.
both 95s because to average you add them all and divine by the number of things your adding by
96+86+78+95+95=450/5=90
