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3 years ago

5

Helpppp

1 answer:

Sonja [21]3 years ago

7 0

The answer is 10.5

Formula for rectangular prism:
L x W x H

L = 3
W = 7/4, which equals 1.75
H = 2

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During a sale each item in the store is 80% off it's regular price if the regular price of a t-shirt is $18 how much is the disc

7nadin3 [17]

Answer:

so u will pay 3.82 and u will save 15.26 dollars

Step-by-step explanation:

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3 years ago

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Given f (x) = startlayout enlarged left-brace first row 3 startroot 2 x minus 1 endroot, for x less-than-or-equal-to 2 second ro

qwelly [4]

<u>These 2 equations has </u><u>no solution</u><u> and the equations are </u><u>independent</u><u> </u><u>of each other.</u>

What is liner equation with two variable?

An equation is said to be linear equation in two variables if it is written in the form of ax + by + c=0, where a, b & c are real numbers and the coefficients of x and y, i.e a and b respectively, are not equal to zero.
For example, 10x+4y = 3 and -x+5y = 2 are linear equations in two variables.

-10x² -10y² = -300 ----a

5x² + 5y² = 150 ---- b

While trying to solve this,

We can multiply the eq. b by 2 so we will get eq. c and then add to eq. a we will get 0 as the solution.

10x² + 10y² = 300 ----c

-10x² -10y² = -300 ---a

<u>Everything cutoff, we will </u><u>get 0</u><u>, and there is no solution to these equations.</u>

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8 0

2 years ago

PLEASE HELP ITS DUE SOON IM SO CONFUSED! HELP NEEDED!!

ddd [48]

Answer:

<u>e</u>

Step-by-step explanation:

According to Angle Sum Property :

<u>∠A + ∠B + ∠C = 180°</u>

<u />

============================================================

Given :

⇒ ∠A = 50°

⇒ ∠B = 32°

===========================================================

Solving :

⇒ 50° + 32° + ∠C = 180°

⇒ ∠C + 82° = 180°

⇒ ∠C = <u>98°</u>

6 0

2 years ago

Q3: Identify the graph of the equation and write and equation of the translated or rotated graph in general form. (Picture Provi

natta225 [31]

Answer:

b. circle; $2(x')^2+2(y')^2-5x'-5\sqrt{3}y'-6 =0$

Step-by-step explanation:

The given conic has equation;

$x^2-5x+y^2=3$

We complete the square to obtain;

$(x-\frac{5}{2})^2+(y-0)^2=\frac{37}{4}$

This is a circle with center;

$(\frac{5}{2},0)$

This implies that;

$x=\frac{5}{2},y=0$

When the circle is rotated through an angle of $\theta=\frac{\pi}{3}$ ,

The new center is obtained using;

$x'=x\cos(\theta)+y\sin(\theta)$ and $y'=-x\sin(\theta)+y\cos(\theta)$

We plug in the given angle with x and y values to get;

$x'=(\frac{5}{2})\cos(\frac{\pi}{3})+(0)\sin(\frac{\pi}{3})$ and $y'=--(\frac{5}{2})\sin(\frac{\pi}{3})+(0)\cos(\frac{\pi}{3})$

This gives us;

$x'=\frac{5}{4} ,y'=\frac{5\sqrt{3} }{4}$

The equation of the rotated circle is;

$(x'-\frac{5}{4})^2+(y'-\frac{5\sqrt{3} }{4})^2=\frac{37}{4}$

Expand;

$(x')^2+(y')^2-\frac{5\sqrt{3} }{2}y'-\frac{5}{2}x'+\frac{25}{4} =\frac{37}{4}$

Multiply through by 4; to get

$4(x')^2+4(y')^2-10\sqrt{3}y'-10x'+25 =37$

Write in general form;

$4(x')^2+4(y')^2-10x'-10\sqrt{3}y'-12 =0$

Divide through by 2.

$2(x')^2+2(y')^2-5x'-5\sqrt{3}y'-6 =0$

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3 years ago

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