Answer:
Distance of JK = 15 unit
Step-by-step explanation:
Given:
J(4,8)
K(-1,-2)
Find:
Distance of JK
Computation:
Distance = √(x₂-x₁)² + (y₂-y₁)²
Distance of JK = √(-1-4)² + (-2-8)²
Distance of JK = √25 + 100
Distance of JK = √125
Distance of JK = 15 unit
Answer:
120 min
or
2 hrs
Step-by-step explanation:
60 min=1 hr
60 min/5=12 min
12(4)=48 min
24 min=1/5 of room
24(5)=120 min
120 min=2 hrs
Side = 8m
He increases length by 2m and reduces width by 2m
(a.) New dimensions will be -
Length = 10m and Width = 6m
(b.) Area = length x breadth (or width)
here we will use the special product (x+y) (x-y)
length = (x+y) and width = (x-y)
area = (8+2) x (8-2)
8^(2) - 2^(2)
= 60
(2(8)-12)+(12(8)(2)-10)
(16-12)+(132-10)
4+122=126
THE ANSWER WOULD BE 126 :D
