Answer:
θ = 5π/6 rad and 11π/6 rad
Step-by-step explanation:
Given the expression cotθ+√3=0
Subtract √3 from both sides
cotθ+√3-√3=0-√3
cotθ = -√3
Since cotθ = 1/tanθ
1/tanθ = -√3
Reciprocate both sides:
tanθ = -1/√3
θ = tan^-1(-1/√3)
θ = -30°
Since the angle is negative, and tanθ is negative in the second and fourth quadrant.
In the second quadrant;
θ = 180-30
θ = 150°
Since 180° = πrad
150° = 150π/180
150° = 5π/6 rad
In the fourth quadrant;
θ = 360-30
θ = 330°
Since 180° = πrad
330° = 330π/180
330° = 11π/6 rad
Hence the solutions are 5π/6 rad and 11π/6 rad.
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Answer:
11
Step-by-step explanation:
Replace the variable xx with −1-1 in the expression.
f(−1)=−3⋅−1+8f(-1)=-3⋅-1+8
Simplify the result.
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Multiply −3-3 by −1-1.
f(−1)=3+8f(-1)=3+8
Add 33 and 88.
f(−1)=11f(-1)=11
The final answer is 1111.
=11
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