For this case we have the following function:

When evaluating x = 2 in the given function we have:

Rewriting we have:


Therefore, the pair ordered for this point is given by:

The ordered pair of the table for x = 2 is:

Therefore, the table is incorrect for x = 2
Answer:
The row in the table is incorrect for:
x=2
I think it would be the second answer but I’m not positive
Answer:
A
Step-by-step explanation:
(2b-3)^2 = (2b-3)(2b-3) = 4b^2-12b+9
Answer:
The correct prove will be:

Step-by-step explanation:

Multiply and Divide by 
= 
⇒ Let
= Ф and 7Ф = 
= sin2Ф sin3Ф sin5Ф ÷ 2cosФ
= 1/2(2sin2Фsin5Ф)sin3Ф ÷ 2cosФ
= (cos3Ф - cos7Ф) sin3Ф ÷ 4cosФ
= 1/2(2cos3Ф sin3Ф) ÷ 4cosФ ∵cos7Ф = 0
= sin6Ф ÷ 8cosФ
= sin(7Ф - Ф) ÷ 8cosФ
= (sin7ФcosФ - cos7ФsinФ) ÷ 8cosФ ∵sin7Ф = 1
= cosФ ÷ 8cosФ
= 1/8
Hence, The correct prove will be:

Keywords: prove, sinФ, cosФ
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