Question

Help me!!!!!!!!!!!!!

Answer 1

For this case we have the following function:

$y=\frac{3}{4}x^2$

When evaluating x = 2 in the given function we have:

$y=\frac{3}{4}(2)^2$

Rewriting we have:

$y=\frac{3}{4}(4)$

$y=3$

Therefore, the pair ordered for this point is given by:

$(x, y) = (2,3)$

The ordered pair of the table for x = 2 is:

$(x, y) = (2,4)$

Therefore, the table is incorrect for x = 2

Answer:

The row in the table is incorrect for:

x=2