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kirill115 [55]
3 years ago
9

Question -3(-4)= Please help me I don’t know what to do!

Mathematics
1 answer:
kotegsom [21]3 years ago
5 0

Answer:

The answer is 12. Please please like.

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Factor 4x^4yz-16y^3z
Iteru [2.4K]

Answer:

<h2>4x⁴yz - 16y³z = 4yz(x² - 2y)(x² + 2y)</h2>

Step-by-step explanation:

4x^4yz-16y^3z\\\\4x^4yz=4yz\cdot x^4\\\\16y^3z=4yz\cdot4y^2\\\\4x^4yz-16y^3z=4yz\cdot x^4-4yz\cdot4y^2=4yz(x^4-4y^2)\\\\x^4-4y^2=x^{2\cdot2}-2^2y^2=(x^2)^2-(2y)^2=(x^2-2y)(x^2+2y)\\\\Used:\\\\(a^n)^m=a^{nm}\\\\(ab)^n=a^nb^n\\\\a^2-b^2=(a-b)(a+b)\\\\4x^4yz-16y^3z=4yz(x^2-2y)(x^2+2y)


6 0
3 years ago
Six friends share cost of gift. They pay $90 and receive $42 in change. How much does each pay?
miskamm [114]
Lets look at the info we have:-

6 friends
Pay $90 and receive $42 in change.

Question:-

How much does each friend pay?

To answer this first we nee to find out how much they paed in total. lets do that 1st:-

90 - 42 = 48
They paid $48 for the gift.

CHECK OUR WORK:-

48 + 42 = 90
We were RIGHT!!

Now lets divide to find out how much each person paid:- 

48 ÷ 6 = 8
Each friend pays $8.

CHECK OUR WORK:-

8 × 6 =  48
We were RIGHT!!

So, each friend pays $8 for the gift.

Hope I helped ya!! xD
7 0
3 years ago
Read 2 more answers
In the given diagram if AB || CD, ∠ABO = 118° , ∠BOD = 152° , then find the value of ∠ODC.
GaryK [48]

Answer:

90°

Step-by-step explanation:

Through point O draw a ray on left side of O which is || to AB & CD and take any point P on it.

Therefore,

∠ABO + ∠BOP = 180° (by interior angle Postulate)

118° + ∠BOP = 180°

∠BOP = 180° - 118°

∠BOP = 62°.... (1)

Since, ∠BOP + ∠POD = ∠BOD

Therefore, 62° + ∠POD = 152°

∠POD = 152° - 62°

∠POD = 90°.....(2)

∠POD + ∠ODC = 180° (by interior angle Postulate)

90° + ∠ODC = 180°

∠ODC = 180° - 90°

\huge\red {\boxed {m\angle ODC =  90°}}

6 0
4 years ago
Solve this to get brainiest ​
Eddi Din [679]

Answer:

1 a. commutative property of multiplication

b. distributive property of multiplication

2 x=23\12

-x = -23\12

-23\12+23\12=0

thus -(-x)+x

6 0
3 years ago
Read 2 more answers
3n^5 ÷ 6n^3, using properties of exponents
Dovator [93]

Answer:

Step-by-step explanation:

\frac{a^{m}}{a^{n}}=a^{m-n}\\\\\frac{3n^{5}}{6n^{3}}=\frac{3}{6}*n^{5-3}\\\\=\frac{1}{2}n^{2}

3 0
3 years ago
Read 2 more answers
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