Sum of interior angles of a polygon of n sides = (n-2)X 180
<span>16-gon = 16-2 = 14 X 180 </span>
<span>1 angle = 14 X 180/ 16 = 157.5 * OR 158 * ANSWER is d</span>
Answer:
if they are choices then its 4 m
Step-by-step explanation:
it cant be the other ones
Step-by-step explanation:
Compare the ratios of their heights, widths, and lengths. If they're the same, then the solids are similar.
10/5 = 2
6/3 = 2
6/3 = 2
The ratios are the same, so the solids are similar.
Answer:
x = A/7
Step-by-step explanation:
Given that the screen is rectangular, recall that the area A of a rectangle whose length is L and width is W is given as
A = L * W
Hence if the width is 7 inches and the length is x inches then the area which is A square inches is connected to both sides as
A = x * 7
Divide both sides by 7
x = A/7 inches
Answer:
A. 12.68 - 14.72 hours
B. Normal distribution.
Step-by-step explanation:
Part A
This question is using quantitative data. A 99% confidence interval means that you want to know the range where 99% of the population will be. To find this you have to convert the 99% CI into the z-score which is -2.58SD to + 2.58SD.
Note that the standard deviation(SD) is from the sample, not the population. We still need to find the standard deviation of the population. The formula is:
population SD =
Where the o= sample SD = 7.4
n= number of sample = 463
The calculation will be:
population SD =
population SD = = 0.3951
The bottom limit will be:
Mean - SD * z-score= 13.7 - 0.3951*2.58 = 12.68 hours
The upper limit will be:
Mean + SD * z-score= 13.7 + 0.3951*2.58 =14.72 hours
The 99% CI range will be 12.68 - 14.72 hours
Part B
The table used to convert confidence interval into z-score depends on the distribution type of the data. Most data is classified as normal distributed, a data type that will concentrated at mean and spread equally from the mean. Normal distribution data will look like a bell which make it also called bell curve.
The question tells you that the data is normal distribution, but that doesn't mean every data is normally distributed. There are a lot of other data distribution type so we have to do some tests to know the normality of the data in real-life data.