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Nookie1986 [14]
3 years ago
9

Among all rectangles that have a perimeter of 202, find the dimensions of the one whose area is largest. Write your answers as f

ractions
reduced to lowest terms.
Mathematics
1 answer:
kolezko [41]3 years ago
8 0

Answer:

How to write by fraction? 50 1/2 by 50 1/2

Step-by-step explanation:

the maximum area for a rectangle is a square.

To find a square with p = 202, divide it by 4,

202 / 4 = 50.5

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6-4x=(3-x)<br> A) -2<br> B) 2<br> C) all real, numbers<br> D) no solution
Semmy [17]
6 - 4x = (3 - x)

Subtract 6 from both sides, as well as adding x to both sides.

-4x + x = 3 - 6

Add like terms.

-3x = -3

Divide both sides by -3.

x = 1

So, your answer is c) All real, numbers because all of the other answer choices are wrong. 

We know this because a) and b) are incorrect. To know if they are incorrect, you just plug in the numbers. When 2 and -2 are plugged into the equation, it is incorrect. So, you solve the equation, and you now know that it is not D) because there is a solution. 

So, once again, your answer is C.

~Hope I helped!~

6 0
3 years ago
Read 2 more answers
Find the number of sides of a regular polygon if one interior angle is 120 degrees
nikitadnepr [17]

Answer:

Triangle(C)

Step-by-step explanation:

All the Exterior Angles of a polygon add up to 360°, so: each exterior angle must be 360°n (where n is the number of sides). So, 360n=120 ; n=360/120=3 It is a triangle.

6 0
3 years ago
Read 2 more answers
A university offers 3 calculus classes: Math 2A, 2B and 2C. In both parts, you are given data about a group of students who have
ankoles [38]

Answer:

4 students

Step-by-step explanation:

The total number of students is given by:

|A|+|B|+|C|-|A\cap B|-|A\cap C|-|B\cap C| + |A\cap B \cap C| = N

Where N is the total number of students, A is the number of students that have taken Math 2A, B is the number of students that have taken Math 2B, and C is the number of students that have taken Math 2C:

|A|+|B|+|C|-|A\cap B|-|A\cap C|-|B\cap C| + |A\cap B \cap C| = N\\51+80+70-15-20-13 +  |A\cap B \cap C|  = 157\\ |A\cap B \cap C| =4

4 students in Group A have taken all three classes.

*The number of students that have taken two classes has be subtracted so those students do not get counted twice

4 0
4 years ago
450 high school freshmen were randomly selected for a national survey. Among survey participants, the mean grade-point average (
umka21 [38]

Answer:

The margin of error is of 0.01.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.7}{2} = 0.15

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.15 = 0.85, so Z = 1.037.

The margin of error is of:

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

Standard deviation was 0.21.

This means that \sigma = 0.21

Sample of 450:

This means that n = 450

What is the margin of error, assuming a 70% confidence level, to the nearest hundredth?

M = z\frac{\sigma}{\sqrt{n}}

M = 1.037\frac{0.21}{\sqrt{450}}

M = 0.01

The margin of error is of 0.01.

4 0
3 years ago
The number of users on a website has grown exponentially since its launch. After 2 months, there were 90 users. After 4 months,
grigory [225]

Answer:

10(3)^x

Step-by-step explanation:

The function contains the points (2,90) and (4,810). Use the general form y=abx to write two equations:

90=ab^2 and 810=ab^4

Solve each equation for a:

a=90/b^2 and a=810/b^4

Since a=a, set the other sides of the equations equal and solve for b.

90/b2=810/b4

Cross multiply, then divide and simplify as follows:

90b^4=810b^2

b^4/b^2=810/90

b^2=90

b^3

Now, use the value of b and the point (2,90) to find the value of a.

90=a(3^2)

a=10

So, substitute answers in original equation for a final answer of f(x)=10(3)^x.

8 0
3 years ago
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