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Vinil7 [7]
3 years ago
11

(7,5), (r, 9), m= 6​

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
3 0

Answer:

www,mathpapa.com

Step-by-step explanation:

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A tree is 4<br> is 4.4 feet tall. It is expected to grow by 1 feet per year.
LekaFEV [45]

Answer:

it should be 10.4 in 6 years.

Step-by-step explanation:

not sure what you were asking.

6 0
2 years ago
PLZZZ HELP ME <br> Evaluate the expression <br> 4 • 6(2 + 9√) + 1.
KonstantinChe [14]

Answer:

121 assuming that 9\\ \sqrt \\ is the square root of 9

Step-by-step explanation:

I plugged it into my calculator, but use PEMDAS and you can get the answer.

7 0
2 years ago
Read 2 more answers
Nate works at least 4 hours but not more than 9 hours. He earns $12.40 per hour. The function f(t) = 12.4t represents the amount
Mashcka [7]

The practical domain is all real numbers from 4 to 9, inclusive.

The practical range is all real numbers from 49.6 to 111.6, inclusive.

These are the correct options.

Explanation:

Given function is f(t) = 12.4t

Let us assume that Nate works 'x' hours so 4<x<9

And multiplying the hours with his earnings we get the range.

4*12.40=49.6 and 9*12.40=111.6. Let the amount earned be represented by y

Hence, domain can be represented as 4<x<9 and range can be represented as  49.6 < y < 111.6

7 0
3 years ago
Joe paid $14.00 for a board game this was 70% of the original price what was the original price
wolverine [178]
70% turns into .70×14.00
4 0
3 years ago
Read 2 more answers
9) Craig earns the same amount
Sloan [31]

<u><em>Answer:</em></u>

Craig earns $1,200 each month

<u><em>Explanation:</em></u>

We are given that Craig pays a total of $720 each year for his telephone service

We also know that a year has 12 months

<u>This means that:</u>

Craig pays \frac{720}{12}= 60 dollars each month for his telephone services

We are given that the monthly phone bill is \frac{1}{20} of his monthly earnings

Assume that his monthly payment is x

<u>We have:</u>

\frac{1}{20}x = PhoneBill\\ \\ \frac{1}{20}x = 60\\ \\   x=60*20 = 1200 dollars

Hope this helps :)

6 0
3 years ago
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