Answer:
36/48 or 6/8 or 3/4 or .75
Step-by-step explanation:
6^2/ [(2+4)*2^3]
6^2/ [ ( 6)*2^3]
36/[(6)*8]
36/48
Explanation:
The angles are <em>vertical angles</em> if the opposites of the rays forming one of the angles are the rays forming the other angle.
More formally, if V is the common vertex, and ...
- R is a point on one of the rays forming Angle 1
- S is a point on the ray that is the opposite of ray VR
- T is a point on the other ray forming Angle 1
- U is a point on the ray that is the opposite of ray VT
Then angle RVT and angle SVU are vertical angles.
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Another way to say this is that points R, V, S are collinear, as are points T, V, U, and the two angles of interest are RVT and SVU.
If the above conditions cannot be met, then the angles are not vertical angles.
First, plot the points. Point R would be somewhere in the second Quadrant, point M would be in the first quadrant 1, point B would be in the fourth quadrant, and point S would be on the negative y-axis. A property of rhombi is that their diagonals are perpendicular. One would need to calculate the slopes of the diagonals and determine whether or not they are perpendicular. Lines are perpendicular if and only if their slopes are opposite reciprocals. Example: 2 and -0.5
Formulas needed:
Slope formula:

The figure would look kinda like this:
R
M
S
B
Diagonals are segment RB and segment SM
So, your slope equations would look like this:

and

Slope of RB= -1
Slope of SM=7
Not a rhombus, slopes aren't perpendicular. But this figure may very well be a parallelogram
Answer:
a, (x^2)^3 = x^6 = x^2.x^4
b, x^5·x^7 = x^12 = (x^3)^4
c, x^4·x^22 = x^26 = (x^2)^13
d, (x^2)^8 = x^16 = x^2.x^14
e, x^10/x^3 = x^7 = x^20.x^(-13)
f, x^(-3) = x^4.x^(-7)
g, 1/x^(-3) = x^3 = x^4.x^(-1)
Hope this helps!
:)