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Zigmanuir [339]
3 years ago
5

Find the sum of the first 40 terms of a geometric sequence where the first term is 16 and the common ratio is 1.1. 704 7,081.480

89 7,805.62898 6,423.16445
Mathematics
1 answer:
Lilit [14]3 years ago
8 0

Step-by-step explanation:

The nth term of a geometric progression can be determined by using the formula:

Tn=arn−1

where: a = first term and r = common ratio

Substitute the given values of first term and common ratio into the formula:

Tn=arn−1

T5=(40)(0.5)5−1

T5=(40)(0.5)4

T5=(40)(0.0625)

T5=2.5

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If f(x) = 2^x + 4 and g(x) = x^2 – 4 what is the value of f(5) +g(-3)
Anon25 [30]

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3 years ago
Triangle LMN similar to triangle OPQ find the measure of side PQ round your answer to the nearest 10th if necessary
sergejj [24]

*see attachement for the triangles given

Answer:

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Step-by-step explanation:

Corresponding sides of similar shapes or figures are proportional to each other. Since ∆LMN ~ ∆OPQ, the ratio of their corresponding sides would therefore be equal. Thus:

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Plug in the values

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2 years ago
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3 0
3 years ago
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vodka [1.7K]

Answer:

I think its $1 every 4 oz

Step-by-step explanation:

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5 0
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Answer:

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