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Zigmanuir [339]
3 years ago
5

Find the sum of the first 40 terms of a geometric sequence where the first term is 16 and the common ratio is 1.1. 704 7,081.480

89 7,805.62898 6,423.16445
Mathematics
1 answer:
Lilit [14]3 years ago
8 0

Step-by-step explanation:

The nth term of a geometric progression can be determined by using the formula:

Tn=arn−1

where: a = first term and r = common ratio

Substitute the given values of first term and common ratio into the formula:

Tn=arn−1

T5=(40)(0.5)5−1

T5=(40)(0.5)4

T5=(40)(0.0625)

T5=2.5

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from the question,

sum of the root will be

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and also, product of the roots will

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