Find the sum of the first 40 terms of a geometric sequence where the first term is 16 and the common ratio is 1.1. 704 7,081.480
89 7,805.62898 6,423.16445
1 answer:
Step-by-step explanation:
The nth term of a geometric progression can be determined by using the formula:
Tn=arn−1
where: a = first term and r = common ratio
Substitute the given values of first term and common ratio into the formula:
Tn=arn−1
T5=(40)(0.5)5−1
T5=(40)(0.5)4
T5=(40)(0.0625)
T5=2.5
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5
Step-by-step explanation:
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