Let T = the distance, in miles, a tire lasts
T ~ N(70000,4400<span>²</span>)
P(T
75000)
= P(Z
)
= P(Z
)
≈ P(Z
1.14)
= 1 - P(Z < 1.14)
≈ 1 - 0.8729
= 0.1271
Answer is 13a + 2b multiply everything in the parenthesis by 2 so 2 x b is 2b and 2 x 5a is 10a so 3a + 10a is 13a + 2b
Answer: (y^2-a)(1+x-b)
Step-by-step explanation:
Factor out the common terms: =x(y^2-a)-by^2+ab+y^2-a
Then rewrite as: =(y^2-a)x-by^2+ab+1 x (y^2-a)
Factor out the common term (y^2 - a): =(y^2-a)(x+1)-by^2+ab
Factor out the common term b: =(y^2-a)(1+x)+b(-y^2+a)
Rewrite as: =(y^2-a)(1+x)-(y^2-a)b
Factor out the common term (y^2 - a): =(y^2-a)(1+x-b)
Complementary angles add up to 90 degrees.
The complement angle to 35 is:
90 - 35 = 55 degrees.
The answer is D.
Answer:
Step-by-step explanation:
![\sf Given \ that \ f(x) = 3x + 2 \\\\Put \ x = 2 \\\\f(2) = 3(2) + 2\\\\f(2) = 6+2\\\\\bold{f(2) = 8}\\\\\rule[225]{224}{2}](https://tex.z-dn.net/?f=%5Csf%20Given%20%5C%20that%20%5C%20f%28x%29%20%3D%203x%20%2B%202%20%5C%5C%5C%5CPut%20%5C%20x%20%3D%202%20%5C%5C%5C%5Cf%282%29%20%3D%203%282%29%20%2B%202%5C%5C%5C%5Cf%282%29%20%3D%206%2B2%5C%5C%5C%5C%5Cbold%7Bf%282%29%20%3D%208%7D%5C%5C%5C%5C%5Crule%5B225%5D%7B224%7D%7B2%7D)
Hope this helped!
<h2>~AnonymousHelper1807</h2>
