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PolarNik [594]
3 years ago
13

Help please ASAP thank you

Mathematics
1 answer:
lesantik [10]3 years ago
3 0

Answer:

150 by 18 or 20

Step-by-step explanation:

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Circle P is shown. Line segment P Q is a radius and has a length of 9. Line Q R is a tangent that intersects the circle at point
Eduardwww [97]

Answer:

X=6

Step-by-step explanation:

We need to remember the theorem that Tangent always makes a right angle at the point of contact with the circle.

Given details-  

PQ=9= circle radius  

QR=12  

As given in the question  

PQ is the radius  

PQ=PY (since both are the radius to the circle)  

⇒If the line QR = tangent than ∠ PQR must be 90°  

Hence Δ PQR is a right-angled triangle with hypotenuse PR  

PQ²+QR²=PR² (Pythagoras theorem)  

∴Substituting the value of PQ, QR  

⇒We get (9)² +(12)² = PR²

PR²= 225  

⇒PR=15  

As clear in figure PR= PY+YR  

∴15=9+x  

⇒ YR(x)= 6cm  

5 0
3 years ago
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Find the height of a tree of angle of elevation of its top changes from 25 degree to 50 degree as the observer advance 15m towar
Natali5045456 [20]

Answer:

  11.5 m

Step-by-step explanation:

The problem can be solved using a trig relation that relates the side opposite the angle to the side adjacent to the angle. That relation is ...

  Tan = Opposite/Adjacent

The lengths of the adjacent sides of the triangle can be found by rearranging this formula:

  Adjacent = Opposite/Tan

__

The "opposite" side of the triangle is the height of the tree, which we can represent using h. The problem statement tells us of a relation between adjacent side lengths and angles:

  h/tan(25°) -h/tan(50°) = 15 . . . . . moving 15 meters changes the angle

  h(1/tan(25°) -1/tan(50°)) = 15

  h = 15·tan(25°)·tan(50°)/(tan(50°) -tan(25°)) = 15(0.55572/0.72545)

  h ≈ 11.4907 . . . . meters

The height of the tree is about 11.5 meters.

7 0
3 years ago
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