Answer:
(x+4)^2+(y+2)^2=5
or
(x-(-4))^2+(y-(-2))^2=5
Step-by-step explanation:
Format for an equation of a circle: (x-h)^2+(y-k)^2=r^2
Center: (1/2*(-6-2),1/2*(-3-1))=(-4,-2)
Radius: sqrt(20)/2 or sqrt(5)
So, it's
(x+4)^2+(y+2)^2=5
or
(x-(-4))^2+(y-(-2))^2=5
you have to plug it into your equation
General formula to determine the equation of the liney - y₁ = m(x - x₁)
(x₁,y₁) is one of the points which lies n the line
m represents the slope
Find the slopeGiven:
(x₁,y₁) = (6,-6)
(x₂,y₂) = (8,8)
We could find the slope by using this formula
m =

Plug in the numbers
m =

m =

m =

m = 7
The slope is 7
Determine the line equationPlug one of the points (you could choose any of points given from the question) and the slope to the formula of line equation
y - y₁ = m(x - x₁)
y - (-6) = 7(x - 6)
y + 6 = 7x - 42
y = 7x - 42 - 6
y = 7x - 48
<em>This is the equation of the line</em>
Answer:

Step-by-step explanation:
When a quadrilateral is inscribed in a circle, the opposite angles of it add up to 180 degrees.
Here,
∠DCB + ∠DAB = 180 (Opposite angles of a quad inscribed in a circle.)
<u>Given that:</u> ∠DCB = 135° and ∠DAB = x
135 + x = 180
Subtract 135 to both sides
x = 180 - 135
x = 55°
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Answer:
I really want to help you but I am really confused with those topics. I am very sorry.
Step-by-step explanation: