Answer:
C $9,318
Step-by-step explanation:
In order to find the answer you have to use the formula provided to calculate the value of the car after t years:
V=C(1-r)^t
C=$21,000
r=15%
t=5
V=21,000*(1-0.15)^5
V=21,000*0.4437
V=9,318
According to this, the answer is that the value of the car after 5 years is $9,318.
Answer:
Step-by-step explanation:
1. ok so 2/3 is the rise over run for x so then 1 is the intercept so the first set of coordinates would be (-1,0) then you would use the rise over run and go up two and over three so the second set of coordinates would be (1,3) and so on
and im not a hundred percent sure on number two
Answer:
![32.10\ \text{mph}](https://tex.z-dn.net/?f=32.10%5C%20%5Ctext%7Bmph%7D)
Step-by-step explanation:
Distance traveled by A in 4 hours = ![24\times 4=96\ \text{mi}=a](https://tex.z-dn.net/?f=24%5Ctimes%204%3D96%5C%20%5Ctext%7Bmi%7D%3Da)
Distance traveled by B in 4 hours = ![22\times 4=88\ \text{mi}=b](https://tex.z-dn.net/?f=22%5Ctimes%204%3D88%5C%20%5Ctext%7Bmi%7D%3Db)
Total distance between A and the initial point of B is ![40+96=136\ \text{mi}](https://tex.z-dn.net/?f=40%2B96%3D136%5C%20%5Ctext%7Bmi%7D)
Distance between A and B 4 hours later
![c=\sqrt{136^2+88^2}\ \text{mi}](https://tex.z-dn.net/?f=c%3D%5Csqrt%7B136%5E2%2B88%5E2%7D%5C%20%5Ctext%7Bmi%7D)
From Pythagoras theorem we have
![(a+40)^2+b^2=c^2](https://tex.z-dn.net/?f=%28a%2B40%29%5E2%2Bb%5E2%3Dc%5E2)
Differentiating with respect to time we get
![2(a+40)\dfrac{da}{dt}+2b\dfrac{db}{dt}=2c\dfrac{dc}{dt}\\\Rightarrow (a+40)\dfrac{da}{dt}+b\dfrac{db}{dt}=c\dfrac{dc}{dt}\\\Rightarrow \dfrac{dc}{dt}=\dfrac{(a+40)\dfrac{da}{dt}+b\dfrac{db}{dt}}{c}\\\Rightarrow \dfrac{dc}{dt}=\dfrac{(96+40)\times24+88\times 22}{\sqrt{136^2+88^2}}\\\Rightarrow \dfrac{dc}{dt}=32.10\ \text{mph}](https://tex.z-dn.net/?f=2%28a%2B40%29%5Cdfrac%7Bda%7D%7Bdt%7D%2B2b%5Cdfrac%7Bdb%7D%7Bdt%7D%3D2c%5Cdfrac%7Bdc%7D%7Bdt%7D%5C%5C%5CRightarrow%20%28a%2B40%29%5Cdfrac%7Bda%7D%7Bdt%7D%2Bb%5Cdfrac%7Bdb%7D%7Bdt%7D%3Dc%5Cdfrac%7Bdc%7D%7Bdt%7D%5C%5C%5CRightarrow%20%5Cdfrac%7Bdc%7D%7Bdt%7D%3D%5Cdfrac%7B%28a%2B40%29%5Cdfrac%7Bda%7D%7Bdt%7D%2Bb%5Cdfrac%7Bdb%7D%7Bdt%7D%7D%7Bc%7D%5C%5C%5CRightarrow%20%5Cdfrac%7Bdc%7D%7Bdt%7D%3D%5Cdfrac%7B%2896%2B40%29%5Ctimes24%2B88%5Ctimes%2022%7D%7B%5Csqrt%7B136%5E2%2B88%5E2%7D%7D%5C%5C%5CRightarrow%20%5Cdfrac%7Bdc%7D%7Bdt%7D%3D32.10%5C%20%5Ctext%7Bmph%7D)
So, the the distance between the ships at 4 PM is changing at ![32.10\ \text{mph}](https://tex.z-dn.net/?f=32.10%5C%20%5Ctext%7Bmph%7D)
Answer:
-9
Step-by-step explanation:
Just plug in
4(-3) - 3(3) - 12(-1)
= -12 - 9 + 12
= -9
X< -3 is the answer to your question.