All categories

3 years ago

Solve each linear-quadratic system algebraically

Mathematics

1 answer:

shusha [124]3 years ago

7 0

For the first one, Y-5=(x-2)^2. First you multiply x-2•X-2, which is x^2-4x+4. Lastly, you subtract -5 from both sides so the equation would look like Y=x^2-4x+9.

You might be interested in

Roger went shoe shopping with his cousins Derek and Kamal. Roger bought a pair of basketball shoes that cost $74.95. Derek spent

bezimeni [28]

Answer:

I'm pretty sure its $19.65

8 0

3 years ago

Which expressions are equivalent to 7 (negative three-fourths x minus 3)? Select two options. Negative 5 and one-fourth x minus

Artist 52 [7]

Answer:

it is b

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Independence and Exclusiveness are two topics which are important to probability and often confused. Discuss the difference betw

Pavlova-9 [17]

Answer:

Independent means that one has no effect on the other. Exclusive means one cannot happen alongside the other. In simpler terms, independent events can be thought of as the chance it'll rain and how many people are flossing their teeth in the morning. Both happen, but neither one impacts the other.

Exclusive, on the other hand, means only one can happen. Lets say at nine in the evening your favorite show is on. However, you have an early morning and should be asleep by nine. You cannot both be asleep and watching your favorite show, and so these events are exclusive.

7 0

3 years ago

Ill Mark Brainliest If you answer Divide 1/2 and 1/8 and express the answer in simplest terms. If necessary, use / for the fract

Yuri [45]

Answer:

Step-by-step explanation:

3 0

3 years ago

A donut store has 11 different types of donuts. You can only buy a bag of 3 of them, where each donut has to be of a different t

MakcuM [25]

Answer:

$165$ .

Step-by-step explanation:

Since repetition isn't allowed, there would be $11$ choices for the first donut, $(11 - 1) = 10$ choices for the second donut, and $(11 - 2) = 9$ choices for the third donut. If the order in which donuts are placed in the bag matters, there would be $11 \times 10 \times 9$ unique ways to choose a bag of these donuts.

In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type $3 \times 2 \times 1 = 6$ times.

For example, if a bag includes donut of type $x$ , $y$ , and $z$ , the count $11 \times 10 \times 9$ would include the following $3 \times 2 \times 1$ arrangements:

$xyz$ .
$xzy$ .
$yxz$ .
$yzx$ .
$zxy$ .
$zyx$ .

Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count $11 \times 10 \times 9$ by $3 \times 2 \times 1 = 6$ to find the actual number of donut combinations:

$\begin{aligned} \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}$ .

Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of $3$ objects from a set of $11$ distinct objects:

$\begin{aligned}\begin{pmatrix}11 \\ 3\end{pmatrix} &= \frac{11 !}{(11 - 3)! \times 3 !} \\ &= \frac{11 !}{8 ! \times 3 !} \\ &= \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}$ .

5 0

2 years ago