Solve each linear-quadratic system algebraically

Mathematics

1 answer:

shusha [124]3 years ago

7 0

For the first one, Y-5=(x-2)^2. First you multiply x-2•X-2, which is x^2-4x+4. Lastly, you subtract -5 from both sides so the equation would look like Y=x^2-4x+9.

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