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3 years ago

Solve each linear-quadratic system algebraically

Mathematics

1 answer:

shusha [124]3 years ago

7 0

For the first one, Y-5=(x-2)^2. First you multiply x-2•X-2, which is x^2-4x+4. Lastly, you subtract -5 from both sides so the equation would look like Y=x^2-4x+9.

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(x +8)(x + 11) = 0<br> Pls help I’m dumb and don’t know this ...

Ivanshal [37]

Answer:

Step-by-step explanation:

x= -8,-11

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3 years ago

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0.580000 as a fraction

Paul [167]

Answer:

$\frac{58}{100}=\frac{29}{50}$

Step-by-step explanation:

Since this is mathematics, significant figures are not necessary. Thus, we can just take 0.58 and delete the 0s. Now, $0.58=\frac{58}{100}$ .

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3 years ago

Implicit diffrention problems I am really stuck on

AysviL [449]

Answer:

$\frac{dy}{dx} =\frac{4x^3+3x^2y-5y^2}{10xy-3y^2-x^3}$

Step-by-step explanation:

solving for dy/dx

multiply the equation out to remove parentheses

$x^4 + x^3y = 5xy^2 -y^3$

now differentiating in terms of x ( $\frac{dy}{dx}$ )

$4x^3 +3x^2y + x^3(\frac{dy}{dx} ) = 5y^2 + 10xy(\frac{dy}{dx} )-3y^2(\frac{dy}{dx} )$

isolating dy/dx to one side

$4x^3 +3x^2y - 5y^2= 10xy(\frac{dy}{dx} )-3y^2(\frac{dy}{dx} )-x^3(\frac{dy}{dx} )$

$4x^3 +3x^2y - 5y^2= \frac{dy}{dx}(10xy-3y^2-x^3)$

$\frac{dy}{dx} =\frac{4x^3+3x^2y-5y^2}{10xy-3y^2-x^3}$

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3 years ago

Tom bought 3 packages of Skittles for $1.25 each. How much did he spend?

polet [3.4K]

Answer:

Tom spent $3.75 of Skittles

Step-by-step explanation:

If each Skittle packet was $1.25, then if that is multiplied by 3, the product of the equation is, 3 dollars and 75 cents/$3.75

1.25 x 3 = 3.75

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If 3/8 of a class is absent what percentage of the class is present

ioda

Answer:

37.5% of the class is present

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3 years ago