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baherus [9]
3 years ago
10

What is m2 2 + m_3? I need the answer please help

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
8 0

Answer:

90

Step-by-step explanation:

because m3+m4 = 90 and m2 and m4 are corresponding angles. therefore m4 = m2 so m3 +m2 = 90

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Which expression is equivalent to
KonstantinChe [14]
Given the expression:

\sqrt[4]{ \frac{24x^{6}y}{128x^{4}y^{5}}}

Simplifying: 

\sqrt[4]{ \frac{3x^{2}}{16y^{4}}}

Then the answer is:

\frac{ \sqrt[4]{3x^{2}}}{2y}


6 0
3 years ago
2. Eliza uses the point (3, 9) to her home’s location and uses the point (6, 13) to represent the ice cream shop’s location. Eac
Elden [556K]

Answer:

I'm gonna use the distance formula:

Distance = sqrt((x2-x1)^2 + (y2-y1)^2)

Distance = sqrt((6-3)^2 + (13-9)^2)

Distance = sqrt(3^2 + 4^2)

Distance = sqrt(9 + 16)

Distance = sqrt(25)

Distance = 5

The problem says every unit = 1 mile so 5 units = 5 miles.

Answer = 5 miles

Step-by-step explanation:

7 0
2 years ago
Write an equation for a circle with a diameter that has endpoints at (–4, –7) and (–2, –5). Round to the nearest tenth if necess
Zinaida [17]

since we know the endpoints of the circle, we know then that distance from one to another is really the diameter, and half of that is its radius.

we can also find the midpoint of those two endpoints and we'll be landing right on the center of the circle.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[-2-(-4)]^2+[-5-(-7)]^2}\implies d=\sqrt{(-2+4)^2+(-5+7)^2} \\\\\\ d=\sqrt{2^2+2^2}\implies d=\sqrt{2\cdot 2^2}\implies d=2\sqrt{2}~\hfill \stackrel{~\hfill radius}{\cfrac{2\sqrt{2}}{2}\implies\boxed{ \sqrt{2}}} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{-2-4}{2}~~,~~\cfrac{-5-7}{2} \right)\implies \left( \cfrac{-6}{2}~,~\cfrac{-12}{2} \right)\implies \stackrel{center}{\boxed{(-3,-6)}} \\\\[-0.35em] ~\dotfill

\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-3}{ h},\stackrel{-6}{ k})\qquad \qquad radius=\stackrel{\sqrt{2}}{ r} \\[2em] [x-(-3)]^2+[y-(-6)]^2=(\sqrt{2})^2\implies (x+3)^2+(y+6)^2=2

4 0
3 years ago
Read 2 more answers
Please help me! Given (x+a)(x+b) = x^2+x-12, what is the value of a^2+b^2
Sonja [21]
(x + 4) (x - 3)
a = 4
b = -3

a^2 + b^2 = ...
= 4^2 + (-3)^2
= 16 + 9
= 25
4 0
3 years ago
2(1 - 3y) - 13x ik the answer idk how to show the work plz help KEY: y = -9 x = 4
AURORKA [14]

Answer:

The answer is 4.

Step-by-step explanation:

2(1 - 3y) - 13x

2(1−(3)(−9))−(13)(4)

56-52

=4

4 0
3 years ago
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