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skelet666 [1.2K]
3 years ago
8

Hi! I need to get this answered right away asap! Waht is 4500, divided by 23400?

Mathematics
2 answers:
ANEK [815]3 years ago
8 0
According to a calculator, this is the answer: 0.1923076923. Hope this helped?
Maslowich3 years ago
6 0
^ that number simplified is 5/26. hope that helps!
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A beverage is made by mixing two parts of water with three part of fruit juice. How many parts of water are mixed with one part
frosja888 [35]

Answer:

2/3

Step-by-step explanation:

good luck !!

3 0
3 years ago
Read 2 more answers
Calculate the pH of a buffer solution made by mixing 300 mL of 0.2 M acetic acid, CH3COOH, and 200 mL of 0.3 M of its salt sodiu
Lesechka [4]

Answer:

Approximately 4.75.

Step-by-step explanation:

Remark: this approach make use of the fact that in the original solution, the concentration of  \rm CH_3COOH and \rm CH_3COO^{-} are equal.

{\rm CH_3COOH} \rightleftharpoons {\rm CH_3COO^{-}} + {\rm H^{+}}

Since \rm CH_3COONa is a salt soluble in water. Once in water, it would readily ionize to give \rm CH_3COO^{-} and \rm Na^{+} ions.

Assume that the \rm CH_3COOH and \rm CH_3COO^{-} ions in this solution did not disintegrate at all. The solution would contain:

0.3\; \rm L \times 0.2\; \rm mol \cdot L^{-1} = 0.06\; \rm mol of \rm CH_3COOH, and

0.06\; \rm mol of \rm CH_3COO^{-} from 0.2\; \rm L \times 0.3\; \rm mol \cdot L^{-1} = 0.06\; \rm mol of \rm CH_3COONa.

Accordingly, the concentration of \rm CH_3COOH and \rm CH_3COO^{-} would be:

\begin{aligned} & c({\rm CH_3COOH}) \\ &= \frac{n({\rm CH_3COOH})}{V} \\ &= \frac{0.06\; \rm mol}{0.5\; \rm L} = 0.12\; \rm mol \cdot L^{-1} \end{aligned}.

\begin{aligned} & c({\rm CH_3COO^{-}}) \\ &= \frac{n({\rm CH_3COO^{-}})}{V} \\ &= \frac{0.06\; \rm mol}{0.5\; \rm L} = 0.12\; \rm mol \cdot L^{-1} \end{aligned}.

In other words, in this buffer solution, the initial concentration of the weak acid \rm CH_3COOH is the same as that of its conjugate base, \rm CH_3COO^{-}.

Hence, once in equilibrium, the \rm pH of this buffer solution would be the same as the {\rm pK}_{a} of \rm CH_3COOH.

Calculate the {\rm pK}_{a} of \rm CH_3COOH from its {\rm K}_{a}:

\begin{aligned} & {\rm pH}(\text{solution}) \\ &= {\rm pK}_{a} \\ &= -\log_{10}({\rm K}_{a}) \\ &= -\log_{10} (1.76 \times 10^{-5}) \\ &\approx 4.75\end{aligned}.

7 0
3 years ago
According to a survey of adults, 64 percent have money in a bank savings account. If we were to survey 50 randomly selected adul
zheka24 [161]

Answer:

The mean number of adults who would have bank savings accounts is 32.

Step-by-step explanation:

For each adult surveyed, there are only two possible outcomes. Either they have bank savings accounts, or they do not. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

E(X) = np

In this problem, we have that:

p = 0.64

If we were to survey 50 randomly selected adults, find the mean number of adults who would have bank savings accounts.

This is E(X) when n = 50.

So

E(X) = np = 50*0.64 = 32

The mean number of adults who would have bank savings accounts is 32.

6 0
3 years ago
Use an equation to find the value of k
Delvig [45]

\boxed{k=4}

<h2>Explanation:</h2>

We know that the slope of a line is given by:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ Where: \\ \\ (x_{1},y_{1}) \ and \ (x_{2},y_{2}) \ are \ points \ that \ lie \ on \ the \ line \\ \\ \\ Here: \\ \\ (x_{1},y_{1})=(-2,k) \\ \\ (x_{2},y_{2})=(2,0) \\ \\ m=-1 \\ \\ \\ -1=\frac{0-k}{2-(-2)} \\ \\ -1=\frac{-k}{4} \\ \\ -k=4(-1) \\ \\ \boxed{k=4}

<h2>Learn more:</h2>

Proportional relationships lines, rates of change, and slope:

brainly.com/question/674693

#LearnWithBrainly

4 0
3 years ago
1. What is the fourth term in the expansion of (x + 4y)^6?
aev [14]
For the fourth term r = 3
Fourth term = 6C3(x)^(6 - 3) (4y)^3 = 20x^3 (64y^3) = 1,280x^3y^3
7 0
3 years ago
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