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2 years ago

Hey! i’ll give brainliest please help

Mathematics

1 answer:

Iteru [2.4K]2 years ago

7 0

Answer:

A subject and a predicate

Step-by-step explanation:

Have a good day :)

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I just need someone to fill in all the answers

Masteriza [31]

Answer:

1. 2

2. 25

3. 1/3

I'm in 8th grade so not 100% sure about these

I'm gonna try the rest

But this is what I got so far!

3 0

2 years ago

Which statement is true about the value of (6)? A.(6) greater-than 6

Anvisha [2.4K]

Answer:

D. (6) is the distance between 6 and 0, and the distance is negative from 6 to 0

Step-by-step explanation:

(6) means the number exists in the negative state. It is -6.

Option A - As it is -6, it cannot be greater than positive 6. So, it is incorrect.

Option B - As it is -6, it cannot be less than negative 6. So, it is wrong.

Option C - As it is -6, its distance cannot be 0 to 6, and it should not be positive.

Option D - As it is -6, its distance should be negative and the distance is from 6 to 0. Therefore, it is the correct answer.

7 0

3 years ago

Given that a × 70 = b<br> work out the value of<br> Your final line should say, 3b/a =...

alukav5142 [94]

a/q b/a=70 so ans will be 210

8 0

3 years ago

Evaluate 18 -8(14 + 4) + 42.

Alina [70]

Answer:

-84

Step-by-step explanation:

4 0

3 years ago

A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 ft/s along

mina [271]

Answer:

The tip of the man shadow moves at the rate of $\frac{20}{3} ft.sec$

Step-by-step explanation:

Let's draw a figure that describes the given situation.

Let "x" be the distance between the man and the pole and "y" be distance between the pole and man's shadows tip point.

Here it forms two similar triangles.

Let's find the distance "y" using proportion.

From the figure, we can form a proportion.

$\frac{y - x}{y} = \frac{6}{15}$

Cross multiplying, we get

15(y -x) = 6y

15y - 15x = 6y

15y - 6y = 15x

9y = 15x

y = $\frac{15x}{9\\} y = \frac{5x}{3}$

We need to find rate of change of the shadow. So we need to differentiate y with respect to the time (t).

$\frac{dy}{t} = \frac{5}{3} \frac{dx}{dt}$ ----(1)

We are given $\frac{dx}{dt} = 4 ft/sec$ . Plug in the equation (1), we get

$\frac{dy}{dt} = \frac{5}{3} *4 ft/sect\\= \frac{20}{3} ft/sec$

Here the distance between the man and the pole 45 ft does not need because we asked to find the how fast the shadow of the man moves.

7 0

3 years ago