Answer:
Step-by-step explanation:
g(x) = x^2 + 6
f(x^2 + 6) = 2(x^2 + 6) + 1 = 2x^2 + 12 + 1 = 2x^2 + 13
D and B are both the answers
Answer:
B (5; 13)
Step-by-step explanation:
Midpoint (x) = (-1 + bx)/2 = 2
Bx - 1 = 4
Bx = 5
Midpoint (y) = (-3 + By)/2 = 5
By - 3 = 10
By = 13
B (5; 13)
When determining the probability that a coin lands on the head more than once, it is first important to know that every time you flip the coin, it has a 50% chance to land head’s up and 50% chance to land tail’s up. The combinations you can get with 4 flips are HHHH, HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTTT, THHH, THHT, THTH, THTT, TTHH, TTHT, TTTH, TTTT. As you can see, there are 16 possible outcomes and 11 of them have head’s coming up more than once. The chances of head’s coming more than once with four tosses of a coin is 68.75% (11/16 times 100)
Answer: D) (x+1)(x + 2)(x-3)
This is because the roots are x = -1, x = -2 and x = 3
Simply get all the numbers to each side to have 0 on the right side
x = -1 turns into x+1 = 0
x = -2 turns into x+2 = 0
x = 3 turns into x-3 = 0
The three factors are (x+1), (x+2) and (x-3)
Which leads to (x+1)(x+2)(x-3)