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kirill115 [55]
3 years ago
11

What is the equation of g​

Mathematics
1 answer:
Goshia [24]3 years ago
4 0

Answer:

the answer would be 67 and the answer would be 887

Step-by-step explanation:

jhdghjsk

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Multiply two and four-fifths negative five and two-thirds.
erik [133]

Answer:

Mixed number: -12 2/15

Improper fraction: -182/15

Step-by-step explanation:

2 4/5 x -5 2/3

First, change into improper fractions

14/5 x -13/3

= -182/15

= -12 2/15

Hope this helps

6 0
4 years ago
Read 2 more answers
If Nancy needs 3/1/4 cups of oatmeal,how many 1/4 cups of oatmeal will she use
PIT_PIT [208]
The answer is 12 1/4. how I got my answer.

Their are 4 quarters to a whole, so that means all I have to do is multiply 4×3=12, then add 1/4+12= 12 1/4.

I hope this helps!
8 0
3 years ago
The U.S. Energy Information Administration (US EIA) reported that the average price for a gallon of regular gasoline is . The US
alexandr1967 [171]

Answer:

The answer is "23, 62, and 139"

Step-by-step explanation:

In point a:

\to \sigma = \$0.24\\\\ \to E = \$0.10\\\\ 95\% \text{confidence level of the z}: \\\\\to \alpha = 1 - 95\% = 1 - 0.95 = 0.05\\\\\to \frac{\alpha}{2} = \frac{0.05}{2} = 0.025\\\\\to Z_{\frac{\alpha}{2}} = Z_{0.025} = 1.96\\\\

 Calculating the sample size:

\to n = (\frac{(Z_{\frac{\alpha}{2}} \times \sigma)}{E})^2

      = (\frac{(1.96 \times 0.24 )}{0.10})^2\\\\= 22.13 \approx 23

In point b:

\to \sigma = \$0.24\\\\\to E = \$0.06\\\\\to Z_{\frac{\alpha}{2}} = Z_{0.025} = 1.96\\\\\to n = (\frac{(Z_{\frac{\alpha}{2}} \times \sigma )}{E})^2\\\\

      = (\frac{(1.96 \times 0.24 )}{0.06})^2\\\\= 61.47 \approx 62

In point c:

\to \sigma = \$0.24\\\\\to E =\$0.04\\\\\to Z_{\frac{\alpha}{2}} = Z_{0.025} = 1.96\\\\\to n = (\frac{(Z_{\frac{\alpha}{2}} \times \sigma )}{E})^2\\\\

      = (\frac{(1.96\times 0.24 )}{0.04})^2 \\\\=138.30 \approx 139    

4 0
3 years ago
Find the length of each segment.<br> W X<br> Y<br> --5<br> 0<br> 5<br> 5. WX<br> 6. WY
Andrew [12]
WX is 2 WY is 9 because each time it moves it’s moving 1 time
8 0
3 years ago
n a call center the number of received calls in a day can be modeledby a Poisson random variable. We know that, on average, 0.5%
guapka [62]

Answer:Pois(ln(200))

Step-byy-step explanation:

Let N be the number of received calls in a day

That is

N∼Pois(λ).

0.5% = 0.5/100 = 1/200 of no calls

P(N=0)=e^−λ=1/200

-λ=e^(1/200)

λ=in(200)

Our number of calls in a day is distributed Pois(ln(200)).

7 0
4 years ago
Read 2 more answers
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