Answer:
* Elimination; a coefficient in Equation I is an integer multiple of a coefficient in Equation II.
* Elimination; a coefficient in Equation II is an integer multiple of a coefficient in Equation I.
Step-by-step explanation:
Equation I: 4x − 5y = 4
Equation II: 2x + 3y = 2
These equation can only be solved by Elimination method
Where to Eliminate x :
We Multiply Equation I by a coefficient of x in Equation II and Equation II by the coefficient of x in Equation I
Hence:
Equation I: 4x − 5y = 4 × 2
Equation II: 2x + 3y = 2 × 4
8x - 10y = 20
8x +12y = 6
Therefore, the valid reason using the given solution method to solve the system of equations shown is:
* Elimination; a coefficient in Equation I is an integer multiple of a coefficient in Equation II.
* Elimination; a coefficient in Equation II is an integer multiple of a coefficient in Equation I.
Answer:
c+2c+12=75
c = 21
Steps:
c+2c+12=75
Simplify both sides of the equation.
c+2c+12=75
(c+2c)+(12)=75(Combine Like Terms)
3c+12=75
3c+12=75
Subtract 12 from both sides.
3c+12−12=75−12
3c=63
Divide both sides by 3.
Answer:
(x+7)^2+4
Step-by-step explanation:
(x+7)^2 + 4
x^2+14x+49+4
x^2+24x+53
