The point-slope form of the equation for a line can be written as
... y = m(x -h) +k . . . . . . . for a line with slope m through point (h, k)
Your function gives
... f'(h) = m
... f(h) = k
a) The tangent line is then
... y = 5(x -2) +3
b) The normal line will have a slope that is the negative reciprocal of that of the tangent line.
... y = (-1/5)(x -2) +3
_____
You asked for "an equation." That's what is provided above. Each can be rearranged to whatever form you like.
In standard form, the tangent line's equation is 5x -y = 7. The normal line's equation is x +5y = 17.
Answer:
1. (5x - 2) + (2x - 2) + x = 
2. m<J = 
3. m<K = 
4. m<L = 
Step-by-step explanation:
Generally, the sum of angles in a triangle =
.
So that;
m<J + m<K + m<L = 
(5x - 2) + (2x - 2) + x = 
5x + 2x + x -2 -2 = 
8x - 4 = 
8x =
+ 4
8x = 184
x = 
x = 
Thus,
m<J = (5x - 2)
= 5(23) - 2
= 
m<K = (2x -2)
= 2(23) - 2
= 
m<L = x
= 
The line is solid and under the line is shaded
so the answer is A
Answer:
Step-by-step explanation:
ur mom (94)
Answer:
x > -11
Step-by-step explanation:
<u>Step 1: Subtract 6 from both sides</u>
-4x + 6 - 6 < 50 - 6
-4x < 44
<u>Step 2: Divide both sides by -4</u>
-4x / -4 < 44 / -4
If you divide by a negative number, you flip the sign.
<em>x > -11</em>
Answer: x > -11