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wariber [46]
2 years ago
13

Which postulate proves the two triangles are congruent?

Mathematics
1 answer:
sammy [17]2 years ago
5 0

Answer:

<em>AAS</em>

Step-by-step explanation:

<em>because</em><em> </em><em>here </em><em>it </em><em>is </em><em>given</em><em> </em><em>that </em><em>two </em><em>angle </em><em>are</em>

<em> </em><em>equal</em>

and a side is common between both traingle

so, both traingle are congruent by

<em><u>AAS</u></em>

hope it helps

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3 years ago
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In the circle below, suppose m VUX = 152° and mZUVW = 77º. Find the following.
bezimeni [28]

Given:

In the circle, m(\overarc{VUX})=152^\circ and m(\angle MUV)=77^\circ.

To find:

The following measures:

(a) m\angle VUX

(b) m\angle UXW

Solution:

According to the central angle theorem, the central angle is always twice of the subtended angle intercepted on the same same arc.

m(VUX)=2\times m\angle VWX

152^\circ=2\times m\angle VWX

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In a cyclic quadrilateral, the opposite angles are supplementary angles.

UVWX is a cyclic quadrilateral. So,

m\angle VUX+m\angle VWX=180^\circ          [Opposite angles of a cyclic quadrilateral]

m\angle VUX+76^\circ=180^\circ

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m\angle VUX=104^\circ

Now,

m\angle UXW+m\angle UVW=180^\circ          [Opposite angles of a cyclic quadrilateral]

m\angle UXW+77^\circ =180^\circ

m\angle UXW=180^\circ-77^\circ

m\angle UXW=103^\circ

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7 0
2 years ago
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2 years ago
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Answer:

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