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storchak [24]
1 year ago
6

Please help me! Which congruence statement does not necessarily describe the triangle shown if DEF equals FGH?

Mathematics
1 answer:
andre [41]1 year ago
7 0

ΔEDF ≅ ΔFGH in this congruence statement does not necessarily describe the triangle shown if DEF equals FGH, so, ΔEDF ≅ ΔFGH is correct answer.

<h3>What is a Congruent triangles :</h3>

Two triangles are said to be congruent if all three corresponding sides are equal and all the three corresponding angles are equal in measure. These triangles can be slides, rotated, flipped and turned to be looked identical. If repositioned, they coincide with each other.

Based on the given conditions,

Since,

ΔDEF ≅ ΔFGH

Then,

∠FED ≅ ∠HGF

∠EFD ≅ ∠GHF

∠EDF ≅ ∠GFH

Congruent triangles corresponding to equal angles,

Therefore,

ΔEDF ≅ ΔFGH in this congruence statement does not necessarily describe the triangle shown if DEF equals FGH.

To learn more about information visit Congruence triangle :

brainly.com/question/12248294

#SPJ1

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Find the corresponding effective interest rate for 3% per year compounded continuously?
jeyben [28]

Answer:

3.045%.

Step-by-step explanation:

We are asked to find the corresponding effective interest rate for 3% per year compounded continuously.

We will use effective interest formula to solve our given problem.

r=e^i-1, where,

r = Effective interest rate,

e = Mathematical constant,

r = Interest rate in decimal form.

Let us convert given interest rate in decimal form.

3\%=\frac{3}{100}=0.03

Substitute values:

r=e^{0.03}-1

r=1.030454533953517-1

r=0.030454533953517

r\approx 0.03045

Convert into percentage:

0.03045\times 100\%=3.045\%

Therefore, the corresponding interest rate would be 3.045%.

3 0
3 years ago
Ben is 4 times old as ishaan. 6 years ago, Ben was 6 times as old as ishaan <br> How old is Ben now?
SpyIntel [72]

Answer:

60years

Step-by-step explanation:

let Ben age = x

ishaan age = y

Ben is 4 times old as ishaan:

x=4y ..........equation (1)

6 years ago

Ben age = x-6

Ishaan age = y-6

x-6=6(y-6)

x-6=6y-36

x=6y-36+6

x=6y-30..........equation (2)

equating equation(1) and (2)

4y=6y-30

4y-6y=-30

-2y=-30

y=-30/-2=15

substituting the value of y into equation (1)

x=4y

=4*15

=60

Ben age now =60years

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in a group of 200 game lover students 120 like cricket and 15 black football West Bengal pin diagram find how many students like
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Your question doesn’t make sense.
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Element X decays radioactively with a half life of 12 minutes. If there are 200
PolarNik [594]

\textit{Amount for Exponential Decay using Half-Life} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{current amount}\dotfill &20\\ P=\textit{initial amount}\dotfill &200\\ t=\textit{elapsed time}\\ h=\textit{half-life}\dotfill &12 \end{cases} \\\\\\ 20=200\left( \frac{1}{2} \right)^{\frac{t}{12}}\implies \cfrac{20}{200}=\left( \frac{1}{2} \right)^{\frac{t}{12}}\implies \cfrac{1}{10}=\left( \frac{1}{2} \right)^{\frac{t}{12}}

\log\left( \cfrac{1}{10} \right)=\log\left[ \left( \frac{1}{2} \right)^{\frac{t}{12}} \right]\implies \log\left( \cfrac{1}{10} \right)=t\log\left[ \left( \sqrt[12]{\frac{1}{2}} \right) \right] \\\\\\ \cfrac{\log\left( \frac{1}{10} \right)}{\log\left[ \left( \sqrt[12]{\frac{1}{2}} \right) \right]}=t\implies \implies \stackrel{mins}{39.9}\approx t

8 0
2 years ago
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