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ladessa [460]
3 years ago
7

_____ returns the smallest integer greater than or equal to 7.3

Computers and Technology
1 answer:
Artist 52 [7]3 years ago
5 0

Answer:

Explanation:

Required

Which returns smallest integer greater than or equal to 7.3

i.e.

x \le 7.3

When executed, the result of each instruction is:

ceil(7.3) = 8 -- This returns the smallest integer greater than 7.3

floor(7.3) = 7 --- This returns the smallest integer less than 7.3

<em></em>larger(7.3)<em> --- there is no such thing as larger() in python</em>

round(7.3) = 7 --- This rounds 7.3 to the nearest integer

From the above result,

8 is the smallest integer greater than or equal to 7.3

i.e.

8 \ge 7.3

Hence:

ceil(7.3) is correct

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Answer:

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In C, developers may access arrays via bracketed syntax like Java or by using * dereferencing notation. The following assignment
Vadim26 [7]

Answer:

See explaination

Explanation:

Square bracket notation is useful when working with objects.

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Below is a representation of the bracket for the question;

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4 years ago
Start with the following Python code. alphabet = "abcdefghijklmnopqrstuvwxyz" test_dups = ["zzz","dog","bookkeeper","subdermatog
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Answer:

alphabet = "abcdefghijklmnopqrstuvwxyz"

test_dups = ["zzz","dog","bookkeeper","subdermatoglyphic","subdermatoglyphics"]

test_miss = ["zzz","subdermatoglyphic","the quick brown fox jumps over the lazy dog"]

# From Section 11.2 of: # Downey, A. (2015). Think Python: How to think like a computer scientist. Needham, Massachusetts: Green Tree Press.

def histogram(s):

   d = dict()

   for c in s:

       if c not in d:

           d[c] = 1

       else:

           d[c] += 1

   return d

#Part 1 Write a function called has_duplicates that takes a string parameter and returns True if the string has any repeated characters. Otherwise, it should return False.

def has_duplicates(stringP):

   dic = histogram(stringP)

   for key,value in dic.items():

       if value>1:

           return True

   return False

# Implement has_duplicates by creating a histogram using the histogram function above. Write a loop over the strings in the provided test_dups list.

# Print each string in the list and whether or not it has any duplicates based on the return value of has_duplicates for that string.

# For example, the output for "aaa" and "abc" would be the following. aaa has duplicates abc has no duplicates Print a line like one of the above for each of the strings in test_dups.

print("***Implementation of has_duplicates fuction***")

for sTr in test_dups:

   if has_duplicates(sTr):

       print(sTr+": has duplicates")

   else:

       print(sTr+": has no duplicates")

#Part 2 Write a function called missing_letters that takes a string parameter and returns a new string with all the letters of the alphabet that are not in the argument string.

#The letters in the returned string should be in alphabetical order. Your implementation should use a histogram from the histogram function. It should also use the global variable alphabet.

#It should use this global variable directly, not through an argument or a local copy. It should loop over the letters in alphabet to determine which are missing from the input parameter.

#The function missing_letters should combine the list of missing letters into a string and return that string.

def missing_letters(sTr):

   missingLettersList = []

   dic = histogram(sTr)

   for l in alphabet:

       if l not in dic:

           missingLettersList.append(l)

   missingLettersList.sort()

   return "".join(missingLettersList)

#Write a loop over the strings in list test_miss and call missing_letters with each string. Print a line for each string listing the missing letters.

#For example, for the string "aaa", the output should be the following. aaa is missing letters bcdefghijklmnopqrstuvwxyz

#If the string has all the letters in alphabet, the output should say it uses all the letters.

#For example, the output for the string alphabet itself would be the following. abcdefghijklmnopqrstuvwxyz uses all the letters

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print("\n***Implementation of missing_letters fuction***")

for lTm in test_miss:

   sTr = missing_letters(lTm.replace(" ",""))

   if sTr!="":

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Answer:

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Therefore, it will be the right answer.

4 0
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Vikki [24]

Answer:

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Explanation:

5 0
3 years ago
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