Answer:
I'll list the answers as coordinates (just input the second number in each coordinate)
(-2, 11)
(0, 1)
(2, -9)
(4, -19)
Step-by-step explanation:
So you see how the x column is filled out? You plug in the numbers in each area and solve for y.
So we start off with -2. You take the x out and place -2 instead. Your equation should look like this:
y = -5 (-2) + 1
Next you multiply -5 and -2, giving you 10. Your equation would look like this now:
y = 10 + 1
Next you add 10 and 1 together, and you have your answer. Keep doing the same thing, but instead of -2 for x, use 0, 2, and 4.
Hope I helped! Have a nice day or night! ^-^
The given equation has no solution when K is any real number and k>12
We have given that
3x^2−4x+k=0
△=b^2−4ac=k^2−4(3)(12)=k^2−144.
<h3>What is the condition for a solution?</h3>
If Δ=0, it has 1 real solution,
Δ<0 it has no real solution,
Δ>0 it has 2 real solutions.
We get,
Δ=k^2−144 here Δ is not zero.
It is either >0 or <0
Δ<0 it has no real solution,
Therefore the given equation has no solution when K is any real number.
To learn more about the solution visit:
brainly.com/question/1397278
By the Pythagorean theorem, the missing side is -sqrt7. The definition of sin is side opposite over hypotenuse, so go into Q2 and make an angle and label the side opposite the angle with a 3 and the hypotenuse a 4. The other leg is -sqrt7 cuz x is negative in Q2. The cosine of an angle is the side adjacent over the hypotenuse, so the cos then is -sqrt7/4
Looks like the graph is decreasing to me
Correct Answer:Option A. 0.01
Solution:This is a problem of statistics and uses the concept of normal distributions. We need to convert the score of 90 into z-score and then find the desired probability from standard normal distribution table.
Converting 90 to z-score:

Now we are to find the probability of z score being more than 2.33. From the z-table the probability comes out to be 0.01.
Therefore, we can conclude that the probability of class average is greater than 90 is 0.01.