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Answer:
5cm
Step-by-step explanation:
Find the diagram attached.
From ΔBCD, ∠BCD = 90-∠ACD
∠BCD = 90-60
∠BCD = 30°
Also tan60 = CD/BD
tan 60 = CD/5
CD = 5tan60
CD = 5√3 cm
Similarly from ΔACD, tan30 = CD/AD
tan30 = 5√3/AD
AD = 5√3/tan30
AD = 5√3/(1/√3)
AD = 5√3 * √3/1
AD = 5 cm
Hence the length of side AD is 5cm
