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DerKrebs [107]
3 years ago
6

Which of the relations are functions?

Mathematics
1 answer:
kramer3 years ago
4 0

Step-by-step explanation:

i tought only S is a function

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Hellooo please i need help on these question
Grace [21]

( f - g )(x) = 10x - 17 and ( f ° g)(-6)  = 60. The answers are option D and B

<h3>There are different type of Function</h3>

Different types of function demands different ways of solving them. Different types are simple function, function by substitution and function of function.

Given that

f(x) = x^{2} + 9x - 14 and g(x) = x^{2} - x + 3

( f - g )(x) will be the difference between f(x) and g(x)

( f - g )(x) = x^{2} + 9x - 14 - ( x^{2} - x + 3)

( f - g )(x) =  x^{2} + 9x - 14 -  x^{2} + x - 3

( f - g )(x) = 10x - 17

Also, if f(x) = 3x^{2} - 15 and g(x) = 1 - 2/3 x

( f ° g)(-6) means that we will evaluate g at -6, then evaluate f at the result of g(-6)

g(-6) = 1 - 2/3 (-6)

g(-6) = 1 + 4

g(-6) = 5

f(g(-6)) = 3(5^{2}) - 15

f(g(-6)) = 3 x 25 - 15

f(g(-6)) = 75 - 15

f(g(-6)) = 60

Therefore, ( f - g )(x) = 10x - 17 and ( f ° g)(-6)  = 60

Learn more about Function here: brainly.com/question/25638609

#SPJ1

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