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eduard
3 years ago
9

Seven times the product of two numbers,a and b,may be written as ?

Mathematics
2 answers:
Vesnalui [34]3 years ago
6 0
I think the answer is 7ab
Softa [21]3 years ago
5 0
It might be 7ab
Hope this helps!
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There are two square roots of 25
kondaur [170]

Answer:

25 and 100

Step-by-step explanation:

5 0
3 years ago
G(x) = 4x + 1<br> What is g(3)?<br> O A. 12<br> O B. 13<br> O C. 8<br> O D. 16
Scrat [10]

Answer:

B. 13

Step-by-step explanation:

g(x)=4x+1

g(3)=4(3)+1

g(3)= 12+1

g(3)=13

6 0
3 years ago
What is the sum of 7/22 and 9/22
natulia [17]
 when u have a common a denominator then you just add the numerator that would be 7 and 9. 7 + 9= 16
so ur solution would be 16/22 and then u would simplify by dividing both values by 2.
so the solution is8/11
8 0
3 years ago
Read 2 more answers
Angles 2 and 7 are called what
Phantasy [73]

Answer:

Alternate Exterior Angles

Step-by-step explanation:

Alternate exterior angles are two angles on the opposite outer sides of two parallel lines cut by a transversal.  

The two angles given, 2 and 7, are alternate exterior angles.

Hope it helps! :)

3 0
2 years ago
Find all the zeros of f(x) help please
Licemer1 [7]

Since f(6)=0, by the remainder theorem this means that <em>x</em> - 6 divides <em>f(x)</em> exactly. This means there are constants <em>a</em>, <em>b</em>, and <em>c</em> such that

\dfrac{f(x)}{x-6} = ax^2 + bx + c

Multiplying both sides by <em>x</em> - 6 gives

f(x) = (x-6)(ax^2+bx+c) \\\\ 2x^3-19x^2+45x-18 = ax^3 + (b-6a)x^2 + (c-6b)x - 6c

Then <em>a</em>, <em>b</em>, <em>c</em> satisfy

\begin{cases}a=2 \\ b-6a=-19 \\ c-6b=45 \\ -6c=-18\end{cases}

and solving this system gives <em>a</em> = 2, <em>b</em> = -7, and <em>c</em> = 3.

So, we have

2x^3-19x^2+45x-18 = (x - 6) (2x^2 - 7x + 3)

The quadratic term can be factored as

2x^2 - 7x + 3 = (2x - 1)(x - 3)

which leaves us with

f(x) = (x-6)(2x-1)(x-3)

so that the zeros of <em>f(x)</em> are 6, 1/2, and 3.

4 0
2 years ago
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