Ask question

Ask question

All categories

3 years ago

15

A jar of olive oil is priced $10.08 for 8 ounces. What is the cost per ounce? If Jan wants to buy 5 jars, how much will she spen

d?

1 answer:

Amanda [17]3 years ago

3 0

Answer:

$1.26 per ounce

5 jars=$50.40

Step-by-step explanation:

$10.08/8 ounces=$1.26 per ounce

$10.08/jar x 5 jars=$50.40

You might be interested in

PLZ HELP ASAP 20 POINTS!! wrote an equation in slope-intercept (y=mx+b) form for each line.

iren [92.7K]

Answer: I’m sorry I cannot explain this any other way because I can not see the answers but —> If you a point that a line passes through, and its slope, this page will show you how to find the equation of the line. ✨

Step-by-step explanation: hope it help you later on!

5 0

2 years ago

Read 2 more answers

Write (8a-^3) -2/3 in simplest form

Anna71 [15]

$(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$

<em><u>Solution:</u></em>

<em><u>Given that,</u></em>

$(8a^{-3})^{\frac{-2}{3}$

We have to write in simplest form

<em><u>Use the following law of exponent</u></em>

$(a^m)^n = a^{mn}$

Using this, simplify the given expression

$(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^{ -3 \times \frac{-2}{3}}\\\\Simplifying\ we\ get\\\\(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^2\\\\We\ know\ that\ 8 = 2^3\\\\Therefore\\\\(8a^{-3})^{\frac{-2}{3}} =2^3^{\frac{-2}{3}} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} =2^{-2} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$

Thus the given expression is simplified

8 0

3 years ago

In Diagram 6, JCK is a tangent to the circle ABC

Igoryamba

Answer:

C

Step-by-step explanation:

if you don't know it choose C

5 0

2 years ago

Consider the function f(x)=−5x−8 and find the following: a) The average rate of change between the points (−1,f(−1)) and (3,f(3)

kipiarov [429]

Answer:

a. -5

b.-5

c.-5

Step-by-step explanation:

In order to find the average rate of change of a function , we divide the change in the output value by the change in the input value.

Generally, the average rate of change (ARC) on an ecuatios between two points (x1,f(x1)) and (x2,f(x2)) is

ARC = [f(x2)-f(x1)]/ (x2-x1)

<em>In case a)</em>

f(-1)= -5*(-1)-8=5-8= -3 f(3)= -5*3-8= -23

Then ARC= (-23-(-3))/(3-(-1))=-20/4=-5

<em>In case b)</em>

f(a)= (-5a-8)

f(b)= (-5b-8)

Then ARC= [(-5b-8)-(-5a-8)]/(b-a)= (-5b+5a)/(b-a)= -5(b-a)/(b-a)= -5

<em>In case c)</em>

f(x)= -5x-8

f(x+h)= -5(x+h)-8= -5x-5h-8

then ARC= [(-5x-5h-8)-(-5x-8)]/(x+h-x) =-5h/h= -5

3 0

2 years ago

Please help me with this question!

nika2105 [10]

Answer:

3

Step-by-step explanation:

3 0

2 years ago