How to describe the behavior of the f (x) from the left and from the right of vertical asymptote

Mathematics

1 answer:

Naddik [55]3 years ago

8 0

Here you go, hope this kinda helps you out :)

You might be interested in

PLEASEEEEEEEE HELPPPPPPO

sattari [20]

I think it is 57 I just subtracted the two numbers

4 0

3 years ago

Solve the equation A = bh for b. b = Ah b = A/h b = h/A b = h – A Solve the equation A = bh for b. b = Ah b = A/h b = h/A b = h

Leto [7]

Answer:

The answer is " $b=\frac{A}{h}$ ".

Step-by-step explanation:

Therefore in this question the "bh" were the multiplied and these values includes the variable which is solving by the isolating of "b".

Let's Divides the both sides for h.

$\to \frac{A}{h} = \frac{bh}{h}\\\\\to \frac{A}{h} = b\\\\\to b= \frac{A}{h}$

7 0

3 years ago

What is the following product? (2 square root 7+3 square root 6)(5 square root 2+4 square root 3)

Xelga [282]

$(2\sqrt7+3\sqrt6)(5\sqrt2+4\sqrt3)\qquad\text{use distributive property}\\\\=(2\sqrt7)(5\sqrt2)+(2\sqrt7)(4\sqrt3)+(3\sqrt6)(5\sqrt2)+(3\sqrt6)(4\sqrt3)\\\\=10\sqrt{14}+8\sqrt{21}+15\sqrt{12}+12\sqrt{18}\\\\=10\sqrt{14}+8\sqrt{21}+15\sqrt{4\cdot3}+12\sqrt{9\cdot2}\\\\=10\sqrt{14}+8\sqrt{21}+15\sqrt4\cdot\sqrt3+12\sqrt9\cdot\sqrt2\\\\=10\sqrt{14}+8\sqrt{21}+(15)(2)\sqrt3+(12)(3)\sqrt2\\\\=\boxed{10\sqrt{14}+8\sqrt{21}+30\sqrt3+36\sqrt2}$