The points you found are the vertices of the feasible region. I agree with the first three points you got. However, the last point should be (25/11, 35/11). This point is at the of the intersection of the two lines 8x-y = 15 and 3x+y = 10
So the four vertex points are:
(1,9)
(1,7)
(3,9)
(25/11, 35/11)
Plug each of those points, one at a time, into the objective function z = 7x+2y. The goal is to find the largest value of z
------------------
Plug in (x,y) = (1,9)
z = 7x+2y
z = 7(1)+2(9)
z = 7+18
z = 25
We'll use this value later.
So let's call it A. Let A = 25
Plug in (x,y) = (1,7)
z = 7x+2y
z = 7(1)+2(7)
z = 7+14
z = 21
Call this value B = 21 so we can refer to it later
Plug in (x,y) = (3,9)
z = 7x+2y
z = 7(3)+2(9)
z = 21+18
z = 39
Let C = 39 so we can use it later
Finally, plug in (x,y) = (25/11, 35/11)
z = 7x+2y
z = 7(25/11)+2(35/11)
z = 175/11 + 70/11
z = 245/11
z = 22.2727 which is approximate
Let D = 22.2727
------------------
In summary, we found
A = 25
B = 21
C = 39
D = 22.2727
The value C = 39 is the largest of the four results. This value corresponded to (x,y) = (3,9)
Therefore the max value of z is z = 39 and it happens when (x,y) = (3,9)
------------------
Final Answer: 39
Answer:
c
Step-by-step explanation:
Step-by-step explanation:
<u>Given functions:</u>
<u>Find (f*g)(6):</u>
- (f*g)(6) = f(6)*g(6) = 6(6 - 1)*3(6) = 30*18 = 540
<u>In case it is a composite function (f · g)(6) the answer is different:</u>
- (f · g)(6) = f(g(6)) = f(3*6) = f(18) = 18*(18 - 1) = 306
I believe that the answer would be:
g(x) = 12x + 17
Answer:
(27.55, 7.22), (-11.3, 3.21).
Step-by-step explanation:
When is the tangent to the curve horizontal?
The tangent curve is horizontal when the derivative is zero.
The derivative is:

Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
.
This polynomial has roots
such that
, given by the following formulas:



In this question:

So

Then

So


Enter your answers as a comma-separated list of ordered pairs.
We found values of t, now we have to replace in the equations for x and y.
t = 3.35


The first point is (27.55, 7.22)
t = -2.685


The second point is (-11.3, 3.21).