Answer:
The lower bound of 19.4 is 19.35
Answer:
51,111%
Step-by-step explanation:
We know that 45% have a dog but no cat. While 23% have both a dog and a cat.
Then Pr(X has cat|X has dog) = Pr(X has dog and cat)/Pr(X has dog)
= Pr(X has dog and cat)/Pr(X has dog) = 0.23/0.45 = 0.51 ≈ 51,111%
The probability that a student’s family owns a cat if the family owns a dog is 51,111%
Answer:
I believe the answer is about 34
Step-by-step explanation:
Answer:
z = (-b + 17)/(a+4)
Step-by-step explanation:
If in terms of a and b, then
az - 17 = -4z - b
z(a-4) = -b+17
z = (-b + 17)/(a+4)
