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hram777 [196]
2 years ago
11

addison and kelsey are running on a path modeled by x^2+y^2-10x-18y-378=0, where the distance is in meters. what is the maximum

distance between the runners at any given time
Mathematics
1 answer:
bulgar [2K]2 years ago
7 0

The maximum distance is the <u>diameter of the circle</u>, which is of 44 units.

The equation of a circle of <u>radius r and center</u> (x_0,y_0) is given by:

(x - x_0)^2 + (y - y_0)^2 = r^2

  • The diameter is <u>twice the radius</u>, and is the <u>maximum distance</u> between two points inside a circle.

In this problem, the circular path is modeled by:

x^2 + y^2 - 10x - 18y - 378 = 0

We complete the squares to place it in the standard format, thus:

x^2 - 10x + y^2 - 18y = 378

(x - 5)^2 + (y - 9)^2 = 378 + 25 + 81

(x - 5)^2 + (y - 9)^2 = 484

Thus, the radius is:

r^2 = 484 \rightarrow r = \sqrt{484} = 22

Then, the diameter is:

d = 2r = 2(22) = 44

The maximum distance is the <u>diameter of the circle</u>, which is of 44 units.

A similar problem is given at brainly.com/question/24992361

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6 0
4 years ago
3.602 × 10 − 4 thx luvs
lorasvet [3.4K]

♡ The Question ♡

- 3.602 × 10 − 4

*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*

♡ The Answer ♡

- 32.02

*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*

♡ The Explanation/Step-By-Step ♡

- 3.602 x 10 - 4

Multiply the numbers: 3.602 x 10 = 36.02

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Subtract the numbers: 36.02 - 4 = 32.02!

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*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*

♡ Tips ♡

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