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4 years ago

9

Pherris is graphing the function f(x) = 2(3)x. He begins with the point (1, 6). Which could be the next point on his graph?

2 answers:

Maurinko [17]4 years ago

4 0

the next point would be (2,18)

Vaselesa [24]4 years ago

3 0

Answer:

2,18

Step-by-step explanation: got it right on e2020

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Learning Task 3:

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Answer:

$Area = x^2- 25$

$Area =9x^2 +24x + 16$

$Length = (3x -2)$

$Speed = \left(y^2-3y+1\right)$

$Product = 3m^3 + 6m^2 - 6m$

Step-by-step explanation:

Solving (1):

$Length = (x + 5)$

$Width = (x - 5)$

Required

Calculate Area

$Area = Length * Width$

$Area = (x + 5) * (x - 5)$

$Area = x^2 + 5x - 5x - 25$

$Area = x^2- 25$

Solving (2):

Given

$Length = (3x + 4)$

Required: Calculate Area

$Area =Length * Length$

$Area =(3x + 4) * (3x + 4)$

$Area =9x^2 + 12x + 12x + 16$

$Area =9x^2 +24x + 16$

Solving (3):

$Area = 3x^2 + 7x - 6$

$Width = x + 3$

Required: Calculate Length

$Area = Length * Width$

$Length = \frac{Area}{Width}$

$Length = \frac{3x^2 + 7x - 6}{x + 3}$

Factorize the numerator

$Length = \frac{3x^2 + 9x -2x - 6}{x + 3}$

$Length = \frac{3x(x + 3) -2(x + 3)}{x + 3}$

$Length = \frac{(3x -2) (x + 3)}{x + 3}$

Divide by x + 3

$Length = (3x -2)$

Solving (4):

$Distance = (2y^3 - 7y^2 + 5y -1)$

$Time = 2y - 1$

Required: Determine the average speed

This is calculated as:

$Speed = \frac{Distance}{Time}$

$Speed = \frac{2y^3 - 7y^2 + 5y -1}{2y - 1}$

Factorize the numerator

$Speed = \frac{\left(2y-1\right)\left(y^2-3y+1\right)}{2y - 1}$

$Speed = \left(y^2-3y+1\right)$

Solving (5):

Multiply $(m^2 + 2m - 2)$ by sum of $(m + 3)$ and $(2m - 3)$

First, calculate the sum:

$Sum = m + 3 + 2m - 3$

$Sum = m + 2m+3 - 3$

$Sum = 3m$

Then, the product

$Product = (m^2 + 2m - 2)(3m)$

$Product = 3m^3 + 6m^2 - 6m$

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Answer:

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Step-by-step explanation:

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Percent mark down= $\frac{decrease in price}{original price} X100$

$=\frac{8-5}{8} X100=\frac{3}{8}X100$

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