1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alex_Xolod [135]
3 years ago
11

Two similar cylinders have volumes of 480cm3 and 60cm3.

Mathematics
1 answer:
ehidna [41]3 years ago
6 0

Answer:

a,480 over 60=80cm3

b,(c over 24)the whole cubed=480 over 60

c*60=24*480

c=11520/60

=192

You might be interested in
2. The water level of a river was measured each day during a two-week period. The
vampirchik [111]

Step-by-step explanation:

day during a two-week period. The

graph models the linear relationship between the water level of the river in feet

and the number of days the water level was measured.

Water Level of River

The initi

28

Ο Ο Ο

The max

24

20

The wate

16

Water Level (ft)

12

o

The water

CLEAR ALL

4

0

2

4

12

6 8 10

Number of Days

Which statement best describes the y-intercept of the graph?

< PREVIOUS

O 3

Os Oo Or

0.8

HH

7 0
2 years ago
Read 2 more answers
On his outward journey, Ali travelled at a speed of s km/h for 2.5 hours. On his return journey, he increased his speed by 4 km/
den301095 [7]

Answer:

3.08 km/h.

Step-by-step explanation:

We know that,

Speed=\dfrac{Distance}{Time}

Ali traveled at a speed of s km/h for 2.5 hours.

Let d be the distance and t be the time.

2.5=\dfrac{d}{t}

2.5t=d      ...(1)

On his return journey, he increased his speed by 4 km/h and saved 15 minutes. So, distance is d and times is t-15.

4=\dfrac{d}{t-15}

4(t-15)=d      ...(2)

From (1) and (2), we get

4(t-15)=2.5t

4t-60-2.5t=0

1.5t=60

t=40

Put t=40 in (1).

d=2.5(40)=100

So, t=40 and d=100.

Now,

Total distance = d + d = 100 + 100 = 200

Total time = t + t - 15 = 40 + 40 - 15 = 65

So, the average speed is

\text{Average speed}=\dfrac{\text{Total distance}}{\text{Total time}}

\text{Average speed}=\dfrac{200}{65}

\text{Average speed}\approx 3.08

Therefore, the average speed is 3.08 km/h.

3 0
3 years ago
What are two equivalent fractions for 1/3
balandron [24]
2/6
3/9
4/12
6/18
8/24
16/48

any three of the above should work for ya hun
7 0
3 years ago
Read 2 more answers
I need help with this someone very smart at math this algebra 2
Mrac [35]

Answer:

value if a =

\frac{5}{4}

Step-by-step explanation:

here's the solution :-

=》

\frac{ 2(\sqrt{m})  {}^{3} }{ \sqrt[4]{m} }

=》

\frac{2(m {}^{ \frac{1}{2}} ) {}^{3} }{ {m}^{ \frac{1}{4} } }

=》

\frac{2 {m}^{ \frac{3}{2} }} { {m}^{ \frac{1}{4} } }

=》

2m {}^{ \frac{3}{2}  -  \frac{1}{4} }

=》

2m {}^{ \frac{6 - 1}{4} }

=》

2m {}^{ \frac{5}{4} }

so, a = 5/4

6 0
2 years ago
Which number line shows point A at 3, point B at −1.5, point C at , and point D, which is the opposite of point A?
Oduvanchick [21]

Step-by-step explanation:

We have that point A is at 3.

This is 3 units to the right of 0 on the number line.

The point that is opposite of A should be 3 units to the left of 0.

That point will be at -3.

Therefore you have to choose the point that is on -3.

It should be similar to one in the attachment.

6 0
2 years ago
Other questions:
  • Two less than is 3 times a number is the number as a equation
    9·1 answer
  • 5x923 in expanded form
    14·1 answer
  • Figure ABCD has vertices A(−4, 1), B(2, 1), C(2, −5), and D(−4, −3). What is the area of figure ABCD?
    14·1 answer
  • Can someone please help me with this question?
    9·1 answer
  • Compare -1/6 and -2/3
    9·2 answers
  • A pole, 4m high, stands, vertically, on
    13·1 answer
  • Interpreting an Expression
    6·1 answer
  • PLEASE HELP ME I ONLY HAVE A FEW MINUTES LEFTTTT!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!Which of the following are irrational numbers?
    7·2 answers
  • 2.8-4.4n-2n+7<br><br><br><br> QUICKLY BRAINLY IF CORRECT
    7·1 answer
  • Ranking the correct answer brainliest !
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!