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2 years ago

A teacher wrote this experssion on the board (-6)(2)+(-8÷4) what is the vaule of this expression

Mathematics

1 answer:

VLD [36.1K]2 years ago

3 0

Answer:

-14

Step-by-step explanation:

(-12)+(-2)

You solve using Pemdas, doing the (-8/4) first, and then doing (-6)(2)

The answer is the two values added together.

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180 is 25% of what number? show ur work

horsena [70]

Since 25% is 1/4, then 180 times 4 is 720.
720 is your answer.

6 0

2 years ago

Determine the slope of the line that passes through the points (-2, 5) (1, -7)

Llana [10]

Answer:

-4

Step-by-step explanation:

Given points

(-2, 5) (1, -7)

Use slope formula to find the slope

m = (y2 - y1)/(x2 - x1)
m = (-7 -5)/(1 + 2) = -12/3 = -4

Slope is -4

5 0

2 years ago

Read 2 more answers

Please help me with the below question.

VMariaS [17]

By letting

$y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}$

we get derivatives

$y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}$

$y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}$

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

$5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0$

Examine the lowest degree term $\left(x^{r-1}\right)$ , which gives rise to the indicial equation,

$5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0$

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients $c_k$ is

$(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}$

so that with r = 4/5, the coefficients are governed by

$c_{k+1} = -\dfrac{c_k}{5k+5} \implies \boxed{g(k) = -\dfrac1{5k+5}}$

c) Starting with $c_0=1$ , we find

$c_1 = -\dfrac{c_0}5 = -\dfrac15$

$c_2 = -\dfrac{c_1}{10} = \dfrac1{50}$

so that the first three terms of the solution are

$\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}$

4 0

2 years ago

27/64A bottled water company has designed a new cup for its dispenser. The cup will be a right circular cone with a three-inch r

tankabanditka [31]

Answer:

9.86 inches

Step-by-step explanation:

Given:

The cup will be a right circular cone with:-

Radius, r = 3 inches

Volume of cone = 93 cubic inches

Height of the cup, h = ?

Solution:

By using :-

$Volume\ of\ right\ circular\ cone=\frac{1}{3} \pi r^{2} h$

$93 =\frac{1}{3} \times\frac{22}{7} \times3\times3\times h\\ \\ 93=\frac{198}{21} h\\ \\ 93=9.43h$

By dividing both sides by 9.43

$\frac{93}{9.43} =\frac{9.43h}{9.43} \\ \\ 9.86\ inches=h$

Thus, the cup need to be 9.86 inches taller to hold 93 cubic inches of water.

6 0

3 years ago

Complete this statement: 20 a x 2 + 25 a x + 15 a = 5 a 20 a x 2 + 25 a x + 15 a = 5 a

liubo4ka [24]

Answer:

Step-by-step explanation:

(((22•5ax2) + 25ax) + 15a) - 5 = 0

Step 2 :

Step 3 :

Pulling out like terms :

3.1 Pull out like factors :

20ax2 + 25ax + 15a - 5 =

5 • (4ax2 + 5ax + 3a - 1)

Equation at the end of step 3 :

5 • (4ax2 + 5ax + 3a - 1) = 0

Step 4 :

Equations which are never true :

4.1 Solve : 5 = 0

4 0

3 years ago