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raketka [301]
3 years ago
8

(2√27 + (5√3)x 6 Can anyone help me out with this plase?

Mathematics
1 answer:
Sphinxa [80]3 years ago
7 0

This is what I got buddy, hope I could possibly help in a way.

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A new company estimates its total profit (profit = total revenue minus total cost) as P(x) = x4 – 2x3 – 240x – 35, where P is in
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4 years ago
Read 2 more answers
MATH Simplify the expression -6w + (-8) + 1 + (-7w)
Luba_88 [7]

Answer: -13w - 7

Step-by-step explanation:

-6w + (-8) + 1 + (-7w)

Combine the like terms

-8 + 1 = -7

-6w + (-7) + (-7w)

-6w + (-7w) = -13w

-13w + (-7)

However, because adding a negative number is the same as subtracting the number as a positive, you can just make it -13w - 7

3 0
3 years ago
Briana is getting materials for a chemistry experiment
satela [25.4K]
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6 0
3 years ago
You are designing a rectangular swimming pool that is to be sent into the ground. The width of the pool is 5 feet more than the
Vikentia [17]

Answer:  depth = 5 ft

width =  10 ft

length =  40 ft

Step-by-step explanation:

d =  depth

width = d + 5

length = d + 36

Volume = length x width x depth = 2000 cf

d(d+35)(d+5) = 2000

d(d^{2} + 40d + 175) = 2000

d^3 + 40d^2 + 175d = 2000

rewrite in standard cubic polynomial form : ax3 + bx2 + cx + d = 0

d^3 + 40(d^2) + 175d - 2000 = 0

Find the roots of the cubic polynomial:

factors of 2000 are 1, 5, 10 15, 20, etc.

Try the factor 5 first by plugging it in the equation:

5^3 + 40(5^2) + 175(5) - 2000 = 0  

Lucky break!  No need to find the other roots because they will be negative, and you can't have a negative value for a pool depth.

So, depth = 5 ft

width = 5 + 5 = 10 ft

length = 5 + 35 = 40 ft

6 0
1 year ago
I need to know the whole thing please help
aleksley [76]

Answer:

a) A student travelling to school on public transport: 15/52 or 0.231

b) A student walking to school: 16/52 or 0.308

c) A student not cycling to school: 43/52 or 0.827

Step-by-step explanation:

Total people = 52

Travel Method          Frequency

Public Transport           12

Car                                 15

Cycle                               9

Walk                                16

Find the relative frequency of.

The formula used will be: Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}

a) A student travelling to school on public transport:

Given Frequency: 12

Size of sample space: 52

Apply formula: Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}

Fraction = 12/52

Decimal = 0.231

b) A student walking to school

Given Frequency: 16

Size of sample space. 52

Apply formula: Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}

Fraction = 16/52

Decimal = 0.308

c) A student not cycling to school.

We will consider all students except those who cycle.

12+15+16 = 43

Given Frequency: 43

Size of sample space. 52

Apply formula: Relative\:Frequency=\frac{Given\: Frequency}{Size\: of\: sample \:space}

Fraction = 43/52

Decimal = 0.827

6 0
3 years ago
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