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3 years ago

At the beginning of a snowstorm, Sydney had 11 inches of snow on her lawn. The

Mathematics

2 answers:

Phantasy [73]3 years ago

5 0

Answer:

Snow after 3 hours: 12.5

Snow after t hours: 11+0.5t

kondor19780726 [428]3 years ago

3 0

Answer:

12.5in.

x=.5t+11

Step-by-step explanation:

First of all, create the equation so you can solve both questions at once. We know that Sydney had eleven inches of snow on her lawn, and it doesn't dissapear, so it starts with x=11. Then every hour she gets .5 inches per hour, and the amount of hours is t, so that will translate to .5t. that makes the equation x=.5t+11. To find out how much she would have in three hours, substitute 3 for t, which which goes like this: x=.5(3)+11

x=1.5+11

x=12.5

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Find the terminal point on the unit circle determined by 7pi//6 radians?

Anit [1.1K]

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210 we can write it as 210 = 180 + 30.
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3 years ago

Which equation can be used to find one multiple of 16? 16 ÷ 8 = 2 16 ÷ 4 = 4 16 × 0 = 0 16 × 2 = 32

lawyer [7]

Answer:

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Step-by-step explanation:

Since you want a multiple, you can ignore anything with a "divided by" symbol in it.

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Multiplying 16 by 2 will give a multiple of 16, as will multiplying 16 by any other non-zero integer.

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3 years ago

Read 2 more answers

The sum of 86, 68, and 38 is 192. What else do you know about the sum of 68, 38, and 86?

Sveta_85 [38]

<span>We have 2 given numbers:
=> 86 + 68 + 38 = 192
=> 68 + 38 + 86 = 192 also
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In the given 2 equations, notice that both digits of 2 group of equation contains the same number. The only difference is they were added with different orders. Yet the answers are still the same.

</span>

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3 years ago

30 Points!!

neonofarm [45]

Answer:

multiply the left side of the constant vector by the inverse matrix

Step-by-step explanation:

The matrix equation ...

AX = B

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IX = A⁻¹B . . . . . the result of multiplying A⁻¹A is the identity matrix

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$\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{cc}-4&1\\3&2\end{array}\right]^{-1}\left[\begin{array}{c}9&7\end{array}\right]=\dfrac{1}{11}\left[\begin{array}{cc}-2&1\\3&4\end{array}\right]\left[\begin{array}{c}9&7\end{array}\right]=\left[\begin{array}{c}-1&5\end{array}\right]$

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3 years ago

Which of the following is true about a parallelogram?

insens350 [35]

Answer:

The diagonals bisect each other.

Step-by-step explanation:

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2 years ago