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3 years ago

Simplify the expression: -10(32-6) ————— 3

Mathematics

2 answers:

iogann1982 [59]3 years ago

7 0

Answer:

-260

Step-by-step explanation:

First, we have to distribute -10 to 32 and -6, since 32 - 6 is in parentheses.

So, the expression becomes -320 + 60, because -10 × 32 = -320 and -10 × -6 = 60.

So, -320 + 60 = -260

skelet666 [1.2K]3 years ago

5 0

Answer: -260

Step-by-step explanation:

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15 pts plz help

RoseWind [281]

Answer:

two the right then below

Step-by-step explanation:

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3 years ago

Jerod is making candles from beeswax. He has 132.72 ounces of beeswax. If each candle uses 8.4 ounces of beeswax, how many whole

photoshop1234 [79]

Answer:

15 candles

Step-by-step explanation:

132.72÷8.4=15.8

therefore jerod can make 15 whole candles

hope this helps

7 0

3 years ago

Help! If you know this can you tell me how to do it?

aleksandr82 [10.1K]

Answer:

Step-by-step explanation:

Here's how this works:

Get everything together into one fraction by finding the LCD and doing the math. The LCD is sin(x) cos(x). Multiplying that in to each term looks like this:

$[sin(x)cos(x)]\frac{sin(x)}{cos(x)}+[sin(x)cos(x)]\frac{cos(x)}{sin(x)} =?$

In the first term, the cos(x)'s cancel out, and in the second term the sin(x)'s cancel out, leaving:

$\frac{sin^2(x)}{sin(x)cos(x)}+\frac{cos^2(x)}{sin(x)cos(x)}=?$

Put everything over the common denominator now:

$\frac{sin^2(x)+cos^2(x)}{sin(x)cos(x)}=?$

Since $sin^2(x)+cos^2(x)=1$ , we will make that substitution:

$\frac{1}{sin(x)cos(x)}$

We could separate that fraction into 2:

$\frac{1}{sin(x)}$ × $\frac{1}{cos(x)}$

$\frac{1}{sin(x)}=csc(x)$ and $\frac{1}{cos(x)}=sec(x)$

Therefore, the simplification is

sec(x)csc(x)

5 0

4 years ago

Use distributive property to write an expression that is equivalent to 6(u+12)

nirvana33 [79]

Answer:

6u + 72

Step-by-step explanation:

6(u + 12)

Distribute 6 to u and 12

6(u) + 6(12)

6u + 72

6 0

3 years ago

A movie theater has n rows and m seats in each row. If each ticket costs $5.60, how much do all tickets to one movie cost?

docker41 [41]

Answer:

All Tickets to one movie cost $\$5.60 \times m\times n$

Step-by-step explanation:

Given:

Number of rows in theater = n

Number of seats in each row = m

Total number of seats in the theater = Number of rows in theater $\times$ Number of seats in each row= $m \times n$

Now given each ticket costs = $\$5.60$

So to find total of all tickets we need multiply each ticket cost by Total number of seats in the theater

Total tickets cost = each ticket cost $\times$ Total number of seats in the theater = $\$5.60 \times m \times n$

3 0

3 years ago