Question

Evaluate the permutation P(36,19)=____

Answer 1

Easy

nPr=$\frac{n!}{(n-r)!}$
here
36P19=$\frac{36!}{(36-19)!}=$
$\frac{36!}{(17)!}=$
$\frac{36*35*34*33*32*31*30*29*28*27*26*25*24*23*22*21*20*19*18}{1}=$
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