Answer:
The best approximation for the area of the shaded region is 
Step-by-step explanation:
<u><em>The complete question is</em></u>
The diameter of the larger circle is 12.5 cm. The diameter of the smaller circle is 8.5 cm.
What is the best approximation for the area of the shaded region?
Use 3.14 to approximate pi.
Small circle inside big circle, shaded region outside smaller circle and inside larger circle
we know that
To find out the area of the shaded region subtract the area of the smaller circle from the area of the larger circle
Remember that
The area of the circle is

so
![A=\pi [r_1^{2}-r_2^{2}]](https://tex.z-dn.net/?f=A%3D%5Cpi%20%5Br_1%5E%7B2%7D-r_2%5E%7B2%7D%5D)
where
r_1 is the radius of the larger circle
r_2 is the area of the smaller circle
we have
---> the radius is half the diameter
---> the radius is half the diameter

substitute
![A=3.14[6.25^{2}-4.25^{2}]](https://tex.z-dn.net/?f=A%3D3.14%5B6.25%5E%7B2%7D-4.25%5E%7B2%7D%5D)

250 is the answer I think
Hi , if 24 pounds of dog food feeds 36 dogs a day , a 16 pound bag is going to feed 28 dogs.
24 - 36
23-35
22-34
21-33
20-32
19-31
18-30
17-29
16-28.
6 pennies, 12 nickels, 8 dimes, 4 quarters = 30 coins
a) add the probability for drawing a dime and drawing a quarter together:
12/30 + 4/30 = 16/30 = 8/15
The probability is 8/15 or 53%
b) multiply the probability for drawing a penny and drawing a nickel:
6/30 x 12/30 = 72/900 = 2/25
The probability is 2/25 or 8%
c) multiply the probability for drawing quarters but take away one of the total coins and the amount of quarters each time:
4/30 x 3/29 x 2/28 = 24/24360 = 1/1015
The probability is 1/1015 or 0.099%
D. There would be one less the second time because one would already be picked.