Question

Factor 4n 2 - 5n - 6. a.(4n - 3)(n + 2) b.(4n + 3)(n - 2) c.(4n + 2)(n - 3)

Answer 1

Answer:

The factorized form of 4n^2 -5n-6 is (4n+3)(n-2)

Step-by-step explanation:

The simplest way to determine the correct factorized form is to expand the equation of each option. Remember:

(a+b)(c+d) =a.c + a.d + b.c + b.d  

Let's calculate the expansion of each factortorized form:

$A)\ (4n-3)(n+2) = 4(n).(n)+(4n)(2)+(-3)(n)+(-3).(2)$

$= 4n^2+8n-3n-6$

$= 4n^2+5n-6$

$B)\ (4n+3)(n-2) = 4(n).(n)+(4n)(-2)+(3)(n)+(3).(-2)$

$4n^2-8n+3n-6$

$4n^2-5n-6$

$C)\ (4n+2)(n-3) = 4(n).(n)+(4n)(-3)+(2)(n)+(2).(-3)$

$=4n^2-12n+2n-6$

$=4n^2-10n-6$

Note that all the option have the same qaudratic (4) and independent (-6) coefficents but only the options B have the same linear coefficents (-5).

Answer 2

The correct answer is this: which is B) It's just backwards (n - 2) • (4n + 3)