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3 years ago

What is greater than 0.58 and less than 0.6

Mathematics

2 answers:

Lady_Fox [76]3 years ago

7 0

Answer:

0.6=3/5

Step-by-step explanation:

Marina86 [1]3 years ago

6 0

Answer:

0.59 im assuming

Step-by-step explanation:

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HELP PLZ!!!! I will give brainlest

bogdanovich [222]

Answer:

Step-by-step explanation:

2.5*18 = 45

So, the answer would be

Yes, this is in the range between 35 psi and 60 psi.

I'm a Clay student, are you too? :) Good luck!!

6 0

3 years ago

Find all the zeros of the equation. -x^3-3x^2=6x+4

k0ka [10]

Answer:

The zeros of given expression $-x^3-3x^2=6x+4$ is -1, $-1+i\sqrt{3}$ and $-1-i\sqrt{3}$

Step-by-step explanation:

Given expresssion is $-x^3-3x^2=6x+4$

To find zeros of given expression we have to equate the expression to zero.

ie., $-x^3-3^2-6x-4=0$

$-(x^3+3x^2+6x+4)=0$

$x^3+3x^2+6x+4=0$

By using synthetic division

-1 | 1 3 6 4

| 0 -1 -2 -4

|________________

1 2 4 0

Therefore (x+1) is a zero

Now the quadratic equation is $x^2+2x+4=0$

For quadratic equation $ax^2+bx+c=0$ we have

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Here a=1 ,b=2 and c=4 now substitute the values

$x=\frac{-2\pm \sqrt{2^2-4(1)(4)}}{2(1)}$

$x=\frac{-2\pm \sqrt{4-16}}{2}$

$x=\frac{-2\pm \sqrt{-12}}{2}$

$x=\frac{-2\pm \sqrt{12i^2}}{2}$ where $i^2=-1$

$x=\frac{-2\pm i \sqrt{4\times 3}}{2}$

$x=\frac{-2\pm i \sqrt{4}\sqrt{3}}{2}$

$x=\frac{-2\pm 2i\sqrt{3}}{2}$

$x=2\times\frac{(-1\pm i\sqrt{3})}{2}$

$x=-1\pm i\sqrt{3}$

Therefore $x=-1+i\sqrt{3}$ and $x=-1-i\sqrt{3}$

Therefore the zeros are -1, $-1+i\sqrt{3}$ and $-1-i\sqrt{3}$

4 0

4 years ago

Look at screen shoot ! math btw again -_-

KIM [24]

Naeem is the correct answer

6 0

3 years ago

Read 2 more answers

Use the trend line to predict what the value of variable N will be when variable M equals 50.

ahrayia [7]

Answer:

N = 10

Step-by-step explanation:

Normally the coordinate system goes:

x axis (horizontal)

y axis (vertical)

Here, we have:

Horizontal axis as "M", and

Vertical axis as "N"

We want to know what N will be when M equals 50.

So, we look at the x-axis and go to M equals 50.

Then we move up until the "trend line". The intersection.

If we move directly left to vertical axis (N variable), we see that it is at the point:

N = 10

So,

When M = 50, N = 10

8 0

4 years ago

Find the value of X

devlian [24]

Answer:

x = 14

Step-by-step explanation:

By tangent secant theorem

$x^2 = 7(7+21)$

$\implies x^2 = 7(28)$

$\implies x ^2=196$

$\implies x=\pm\sqrt{196}$

$\implies x=\pm 14$

x can not be negative

$\implies x=14$

8 0

2 years ago