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Flura [38]
2 years ago
7

I rlly rlly need this badly, pls show work :(

Mathematics
1 answer:
elena55 [62]2 years ago
6 0
1) 2x + 3y = 12 -> 3y = -2x +12 -> y = -2/3x + 4
2) 4y - 7x = 16 -> 4y = 7x + 16 -> y = 7/4x + 4
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Answer:

1.) 6√13/13

2.) 4√13/13

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Step-by-step explanation:

given that cot(x) = 2/3

But cot(x) = 1/tan(x)

Substitutes 1/tan(x) for cot(x)

1/tan(x) = 2/3

Reciprocate both sides

Tan(x) = 3/2 = opposite/adjacent

Use pythagorean theorem to find the hypothenus.

Hypothenus = sqrt ( 3^2 + 2^2 )

Hypothenus = sqrt ( 9 + 4 )

Hypothenus = sqrt (13)

Hypothenus = √13

1.) Sin(x) = opposite/hypothenus = 3/√13

Rationalise

3/√13 × √13/√13

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Sin(2x) = 6√13/13

2.) Cos( x ) = adjacent/hypothenus

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2/√13 × √13 /√13

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Cos(2x) = 4√13/13

3.) Tan (x) = 3/2

tan (2x) = 2 × 3/2

Tan(2x) = 3

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2 years ago
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Answer:

12.9

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AB = \sqrt{2^{2}+3^{2}  } = \sqrt{13}

BC = \sqrt{2^{2}+2^{2}  } = 2\sqrt{2}

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