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MaRussiya [10]
3 years ago
14

Angles formed by parallel lines and transversal

Mathematics
1 answer:
mr_godi [17]3 years ago
3 0
Angle 1 is 113
Angle 2 is 67
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ABCD diagonals intersect at E. If m∠BAC=4x+5 and m∠CAD=5x-14, then find m∠CAD.
Travka [436]

Answer: m∠CAD = 81°

Step-by-step explanation: <u>Diagonal</u> is a line that unites opposite sides.

ABCD is a prallelogram. One property of diagonal in a parallelogram is it separates the parallelogram in 2 congruent triangles.

The figure below shows ABCD with its diagonals.

Since diagonal divides a parallelogram in 2 congruent triangles, it means the internal angles are also congruent. So

m∠BAC = m∠CAD

4x + 5 = 5x - 14

x = 19

Then, m∠CAD is

m∠CAD = 5(19) - 14

m∠CAD = 81

The angle m∠CAD is 81°.

7 0
3 years ago
Solve the right triangle <br>round your answer to the nearest tenth.​
ICE Princess25 [194]

Answer:

Use SOH-CAH-TOA method and figure out which sign you need. SOH- Sin, CAH- Cos, TOA- Tan.

Also,

SOH- opposite/hypotenuse

CAH- adjacent/hypotenuse

TOA- opposite/adjacent

Look at the angle and see which terms you have already. For example, if you had opposite the angle and the adjacent side, you would choose tangent because its TOA. Hope that helps!

6 0
3 years ago
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