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MaRussiya [10]
3 years ago
14

Angles formed by parallel lines and transversal

Mathematics
1 answer:
mr_godi [17]3 years ago
3 0
Angle 1 is 113
Angle 2 is 67
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tekilochka [14]
I think it is 8.83? I am not positive but it is worth a try
7 0
3 years ago
Find the length of the hypotenuse of a right triangle with legs of lengths 12 ft and 16 ft answer
Finger [1]
Use Pythagorus theorem: 

a²+b²=c²
(12)²+(16)²=c²
400=c²
√400=c 
20=c 

Therefore, the hypotenuse would be 20 ft. 

Hope I helped :) 
8 0
3 years ago
The temperature changes from 9°F to -5°F. Which of the following expressions model the distance on thermometer between 9°F and -
scoray [572]

Answer:

d = |- 5- 9|

Step-by-step explanation:

Given

Initial = 9^\circ F

Final = -5^\circ F

Required

Determine the difference

Represent this with d.

d is calculated using

d = |Final - Initial|

The equation becomes

d = |- 5- 9|

3 0
3 years ago
Equivalent expression of x+4+3x
Andreas93 [3]

Answer:

4x+4

Step-by-step explanation:

Combine like terms:

3x+x= 4x

Add remaining terms (+4)

4x+4

4 0
3 years ago
Lou has an account with $10,000 which pays 6% interest compounded annually. if to that account, lou deposits $5,000 at the begin
Tems11 [23]

ince the problem is only asking for 4 years, we can just calculated it out year by year. Recall the formula for compounding interest: A = P(1+r)n, where A is the total amount, P is the principle (amount you start with), r is the interest rate per period of time, and n is the number of periods (in this case, r is annual interest rate, so n is number of years). At the beginning (Year 0), Lou starts off with 10000: A = 10000 At the end of Year 1, Lou earned interest on that amount, plus he has deposited another 5000: A = 10000(1.08) + 5000 End of Year 2, Lou's interest from the year 0 amount has compounded, he has started earning interest on the amount deposited last year, and he deposits another 5000: A = 10000(1.08)2 + 5000(1.08) + 5000 End of Year 3, same idea. Lou has earned compounding interest on all existing deposits, and deposits another 5000: A = 10000(1.08)3 + 5000(1.08)2 + 5000(1.08) + 5000 End of Year 4, same idea: A = 10000(1.08)4 + 5000(1.08)3 + 5000(1.08)2 + 5000(1.08) + 5000 = 36135.45



7 0
3 years ago
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