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irakobra [83]
3 years ago
10

What are the answers?

Mathematics
1 answer:
lina2011 [118]3 years ago
6 0

Heres the first 9 problems im on a time

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What is the solution to the following system of equations?
Alchen [17]

Answer:

it has infinitely many solutions

3 0
3 years ago
Reggie was looking at a map of the school the scale shows that 1 inch equals 150 ft if the distance between his classroom in the
topjm [15]

Answer:

the actual distance is 1800 ft.

Step-by-step explanation:

Proportion states that the two fractions or ratios are equal.

Let x be the actual distance.

As per the statement:

Reggie was looking at a map of the school the scale shows that 1 inch equals 150 ft.

⇒1 inch = 150 ft.

if the distance between his classroom in the cafeteria measures 12 in on the map.

by definition of proportions we have;

\frac{1}{150} = \frac{12}{x}

By cross multiply we have;

x = 12 \cdot 150 = 1,800 ft

Therefore, the actual distance is 1800 ft.

4 0
4 years ago
Read 2 more answers
In triangle JKL, sin(b°) = three fifths and cos(b°) = four fifths. If triangle JKL is dilated by a scale factor of 2, what is ta
scoundrel [369]

Answer:

Tan(b°) = 3/4 = three fourths (C)

Step-by-step explanation:

Triangle JKL is a right angled triangle in which angle K is a right angle and angle L= b°

We would apply SOHCAHTOA from trigonometry to determine the value for each sides.

For ∆JKL

Sin(b°) = opposite/hypotenuse

Sin(b°) = 3/5

Cos(b°) = adjacent/hypotenuse

Cos(b°) = 4/5

Tan(b°) = 3/4

From the above we know the value of each sides of ∆JKL

Find attached the diagram of the above triangle (1)

∆JKL is dilated by a scale factor = 2

Meaning we would multiply each sides of ∆JKL by 2. The values of the new triangle become:

Opposite = 2(3) = 6

Adjacent = 2(4) = 8

Hypotenuse = 2(5) = 10

To find tan(b°) of the new triangle, we would apply tangent ratio

Tan(b°) = opposite/adjacent

Tan(b°) = 6/8

Tan(b°) = 3/4

Find attached the diagram for the new triangle (2)

Diagram 3 shows the drawing of both triangles together.

From the above, we can see the angle doesn't change when a shape is dilated by a scale factor.

Therefore, tan(b°) = three fourths (C)

6 0
3 years ago
An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample
valentina_108 [34]

Answer:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Replacing we got:

\bar X=58.875 represent the mean

s=5.083 represent the sample standard deviation for the sample  

n=8 sample size  

\mu_o =60 represent the value that we want to test

\alpha=0.1 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:  

Null hypothesis:\mu \geq 60  

Alternative hypothesis:\mu < 60  

The statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info we got:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

3 0
3 years ago
I need an answer what is 1.03 ÷ (-10.3)=?
Sloan [31]
The answer is - \frac{1}{10}
To figure this out,  convert both numbers to fractions. 1.03 = 1\frac{3}{100} and (-10.3) = -10\frac{3}{10}. Now, convert to improper fractions. 
 1\frac{3}{100}  = [tex] \frac{103}{100}
-10\frac{3}{10} = - \frac{103}{10}
Now, divide. Dividing fractions is the same as multiplying by the reciporical. So:
-\frac{103}{10}  \ becomes\  \frac{10}{103}
\frac{103}{100} *- \frac{10}{103} =  -\frac{1030}{10300} = - \frac{1}{10}
5 0
3 years ago
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