Answer: No, it is not a solution. It makes the first equation true, but the second equation is false when (x,y) = (16, 1)
To check a possible solution, we replace the variable letters with their actual numbers. The given solution is (x,y) = (16,1) so x = 16 and y = 1 pair up. We'll replace x with 16, and replace y with 1.
Do so with the first equation and simplify
y = (-1/4)*x + 5
1 = (-1/4)*16 + 5
1 = -4 + 5
1 = 1 ... true
And repeat for the second equation
y = (1/6)*x - 2
1 = (1/6)*16 - 2
1 = 2.667 - 2
1 = 0.667 .... false
The equation above is false, so the original equation is false when (x,y) = (16,1). This proves the point is not on the line.
So overall, (16,1) is not a solution to the system.
Answer:
(3x+2) ^2
x = -2/3
Step-by-step explanation:
9x^2+12x+4 = 0
We need to recognize that this is perfect squares
(a + b)2 = a^2 + 2ab + b^2;
Where a = 3x and b =2
a^2 = 9x^2 2ab = 2*3x*2 = 12x and b^2 = 2^2 =4
So we can factor this as (3x+2) ^2
If you want to solve
We can use the zero product property
(3x+2) ^2 =0
Take the square root of each side
3x+2 =0
Subtract 2 from each side
3x=-2
Divide by 3
3x/3 = -2/3
Answer:
Step-by-step explanation:
Sample variance when large number of samples are drawn we have tend to become a normal distribution.
Variance of the sample is different since variance
Var(x) = E(x^2)-{E(x)}^2
is the formula used for finding the variance of any sample.
But sampling distribution of variance requires repeating this process with the different samples several times.
So option A is not right
B is also not correct, C is wrong
D.The sampling distribution of the mean requires multiple samples to be compared. However, in this situation you are looking for the variance, so finding the sample variance is the same as investigating the sampling distribution of the variance.
is correct
Answer:
1/5 gallon per minute
Step-by-step explanation:
The fill rate for container 1 is 2 gallons in 10 minutes. For container 2 it is 4 gallons in 10 minutes. The difference in rates is ...
(4 gal - 2 gal)/(10 min) = 2/10 gal/min = 1/5 gal/min
